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2 years ago

A boy ate 100 cookies in5 days. Each day he ate6 more than the day before. How many cookies did he eat the first day?

Mathematics

1 answer:

Zolol [24]2 years ago

6 0

He ate 8 cookies the first day..... I think this boy now has diabetes.... <span />

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12 divided by 1 1/5 = ? <br><br> IN lowest TERM

kompoz [17]

Answer:

12 divided by 1 1/5 = 60/11 in lowest term

I hope this helps you.

Step-by-step explanation:

Simplify the expression.

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The simple interest I on an investment of P dollars at an interest rate r for t years is given by I = prt. Find the time it woul

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3 years ago

Read 2 more answers

Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (

Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

$P(\frac{T}{S}) = 0.95$

$P(\frac{T}{S^c}) = 0.05$

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

$P(S^c) = 1 - P(S)$

= 1 - 0.3

= 0.7

ii. $P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}$

$= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }$

$= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}$

= 0.8906

iii. $P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}$

$= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }$

$= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}$

= 0.0221

We simply applied the above formulas so that the each part could come

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2 years ago

A eagle has landed in a tree 50 feet above sea level. Directly below the eagle, a seagull is flying 17 feet above sea level. Dir

Luba_88 [7]

Answer:

As attached

Step-by-step explanation:

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2 years ago