Answer:
G. y=2x-5
Step-by-step explanation:
First, find the slope from 2x-y=-3
-y=-2x-3
y=2x+3, which means that the slope is 2
Since it is parallel, the given equation and the line we are finding has the same slope.
let y=mx+b, where m=2, y=5, x=5
5=2(5)+b
5=10+b
-5=b
Thus, y=2x-5
From the identity:


the inverse of f is g such that f(g(x))=x,
we must find g(x), such that
![\frac{1}{cos[g(x)]}=x](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bcos%5Bg%28x%29%5D%7D%3Dx%20)
thus,
![cos[g(x)]= \frac{1}{x}](https://tex.z-dn.net/?f=cos%5Bg%28x%29%5D%3D%20%5Cfrac%7B1%7D%7Bx%7D%20)

Answer: b. g(x)=cos^-1(1/x)
Using product rule;
f(x)=(1+6x²)(x-x²)
f'(x)=(12x)(x-x²) + (1-2x)(1+6x²) = 12x² -12x³ +1 +6x² -2x -12x³ = -24x³ +18x² -2x +1
Solving the bracket first;
f(x)=(1+6x²)(x-x²) = x -x² +6x³ -6x^4
f'(x)= 1 -2x +18x² -24x³ = -24x³ +18x² -2x +1
Answer :
inequality form: k ≥ -4
OR
interval form: [-4, ∞)
Answer:
Step-by-step explanation:
(21²+10²)½ = 23.25= 23.3