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Semenov [28]
2 years ago
14

Use the equation v = StartFraction 10 Over p EndFraction to determine the pressure when the volume is 10 liters. A. 10 c. 100 b.

0. 1 d. 1.
Mathematics
1 answer:
Galina-37 [17]2 years ago
6 0

The value of the pressure is 1 when the value of volume is 10 liters, the correct option is D.

<h3>What is the pressure?</h3>

Pressure is defined as the physical force exerted on an object.

The force applied is perpendicular to the surface of objects per unit area.

Given

The equation is

\rm V=\dfrac{10}{p}

Where the v is the volume and p is the pressure.

The value of p when the value of volume v is 10 liters is;

\rm V=\dfrac{10}{p}\\\\\rm 10=\dfrac{10}{p}\\\\P = \dfrac{10}{10}\\\\P=1

Hence, the value of the pressure is 1.

To know more abour pressure click the link given below.

brainly.com/question/17799294

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(a)

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What is your favorite color? A large survey of countries, including the United States, China, Russia, France, Turkey, Kenya, and
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Answer:

Step-by-step explanation:

We would set up the hypothesis test.

For the null hypothesis,

p = 0.24

For the alternative hypothesis,

p ≠ 0.24

This is a two tailed test

Considering the population proportion, probability of success, p = 0.24

q = probability of failure = 1 - p

q = 1 - 0.24 = 0.76

Considering the sample,

Sample proportion, P = r/n

Where

r = 12

n = 52

P = 12/52 = 0.23

We would determine the test statistic which is the z score

z = (P - p)/√pq/n

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The difference between sample proportion and population proportion(p - P) is 0.24 - 0.23 = 0.01

Since the curve is symmetrical and it is a two tailed test, the p for the left tail is 0.24 - 0.01 = 0.23

the p for the right tail is 0.24 + 0.01 = 0.25

These proportions are lower and higher than the null proportion. Thus, they are evidence in favour of the alternative hypothesis. We will look at the area in both tails. Since it is showing in one tail only, we would double the area

From the normal distribution table, the area below the test z score in the left tail 0.43

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The level of significance is 5%

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