Answer:
if it is a specific equation
then it will all be the same
Step-by-step explanation:
Answer:
See work below
Step-by-step explanation:
The area of a large pizza cut into 10 slices with be 20 square inches. This is from taking the area of a large 200.96 and dividing by 10.
The large pizza will always be cheaper because of economies of scale.
The percent error is 53.3 %
<em><u>Solution:</u></em>
<em><u>The formula for percent error is given as:</u></em>
![Percent\ Error = \frac{\text{ l Experimental value - theoretical value l }}{\text{Theoretical value}} \times 100](https://tex.z-dn.net/?f=Percent%5C%20Error%20%3D%20%5Cfrac%7B%5Ctext%7B%20%20l%20Experimental%20value%20-%20theoretical%20value%20l%20%7D%7D%7B%5Ctext%7BTheoretical%20value%7D%7D%20%5Ctimes%20100)
From given,
A political analyst predicts Mr. Smith will only get 122 votes for mayor
Mr. Smith only gets 57 votes
Therefore,
Theoretical = 122
Experimental = 57
Thus we get,
![\text{Percent Error } = \frac{ | 57-122 | }{122} \times 100\\\\\text{Percent Error } = \frac{65}{122} \times 100\\\\\text{Percent Error } = 0.5327 \times 100\\\\\text{Percent Error } = 53.28 \approx 53.3](https://tex.z-dn.net/?f=%5Ctext%7BPercent%20Error%20%7D%20%3D%20%5Cfrac%7B%20%7C%2057-122%20%7C%20%7D%7B122%7D%20%5Ctimes%20100%5C%5C%5C%5C%5Ctext%7BPercent%20Error%20%7D%20%3D%20%5Cfrac%7B65%7D%7B122%7D%20%5Ctimes%20100%5C%5C%5C%5C%5Ctext%7BPercent%20Error%20%7D%20%3D%200.5327%20%5Ctimes%20100%5C%5C%5C%5C%5Ctext%7BPercent%20Error%20%7D%20%3D%2053.28%20%5Capprox%2053.3)
Thus percent error is 53.3 %
For question one, the easiest way to start is with t=0, so, everything inside the sine function will equal 0, and sin(0) is 0, so that is our starting point. Then, consider the following:
sin(pi/2) = 1
sin(pi) = 0
sin(3pi/2) = -1
sin(2pi) = 0
(You need to know the unit circle)
Then, we see that t=4 is a solution since the 4 times a half is 2, exactly what we need for 2 (pi). Also because it goes around the unit circle.
Problem 2 you just need the period formula. It is [2pi / b] and b is the number in front of t. So we get (2pi / (2pi / 15)). Simplifying leads to 30pi over 2pi which is just 15. Thus the period is 15 units
Lastly, Problem 3 asks for the inverse of a period since the frequency is 1 over the period. Applying the method from the last problem:
2pi / 524pi which simplifies to 1 over 262 is the period.
Now flipping 1 over 262 gives the frequency, which is just 262 by itself
Hope this long explanation helped
Divide percentage by 100 to get to decimal