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Snowcat [4.5K]
3 years ago
7

A square on a coordinate plane has one vertex at ​(3.5​,2​) and a perimeter of 18 units. If all of the vertices are located in Q

uadrant​ I, what are the coordinates of the other 3​ vertices?
Mathematics
1 answer:
Anit [1.1K]3 years ago
5 0

Answer:

Vertex 2 =  (3.5, 6.5)

Vertex 3 = (8, 2)

Vertex 4 = (8, 6.5)

Step-by-step explanation:

Given that:

Perimeter, P = 18 units

Perimeter of a square = 4s ; s = side length

18 = 4s

s = 18/4

s = 4.5 units

If Vertex 1 = (3.5, 2) and all vertexes are located in quadrant 1

Vertex 2 = (3.5, 2+4.5) = (3.5, 6.5)

Vertex 3 = (3.5+4.5, 2) = (8, 2)

Vertex 4 = (8, 2+4.5) = (8, 6.5)

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Step-by-step explanation:

Given the ratio 5:3

and Points A and B where A is located at (-6, 3), and B is located at (26, -13).

Let point A be (x_{1}, y_{1}), and let point B be (x_{2}, y_{2}).

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To solve, just substitute these variables into the expressions of these coordinates to get the answer.

(\frac{nx_{1} + mx_{2}}{n+m}, \frac{ny_{1} + my_{2}}{n + m}) →

(\frac{(5)x_{1} + (3)x_{2}}{(5)+(3)}, \frac{(5)y_{1} + (3)y_{2}}{(5) + (3)}) →

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→

(\frac{6}{1}, \frac{-3}{1})

→

(6, -3).

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\boxed{(6, -3)}

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