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Snowcat [4.5K]
3 years ago
7

A square on a coordinate plane has one vertex at ​(3.5​,2​) and a perimeter of 18 units. If all of the vertices are located in Q

uadrant​ I, what are the coordinates of the other 3​ vertices?
Mathematics
1 answer:
Anit [1.1K]3 years ago
5 0

Answer:

Vertex 2 =  (3.5, 6.5)

Vertex 3 = (8, 2)

Vertex 4 = (8, 6.5)

Step-by-step explanation:

Given that:

Perimeter, P = 18 units

Perimeter of a square = 4s ; s = side length

18 = 4s

s = 18/4

s = 4.5 units

If Vertex 1 = (3.5, 2) and all vertexes are located in quadrant 1

Vertex 2 = (3.5, 2+4.5) = (3.5, 6.5)

Vertex 3 = (3.5+4.5, 2) = (8, 2)

Vertex 4 = (8, 2+4.5) = (8, 6.5)

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\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
X&({{ a}}\quad ,&{{ b}})\quad 
%  (c,d)
Y&({{ -8}}\quad ,&{{ 6}})
\end{array}\qquad
%   coordinates of midpoint 
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\begin{cases}
\cfrac{-8+a}{2}=-3\\\\
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\boxed{a=2}\\
----------\\
\cfrac{6+b}{2}=-1\\\\
6+b=-2\\
\boxed{b=-8}
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