This is the 1st question
1 answer:
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<u>Answer</u>-
<em>The total capacitive reactance of the circuit is </em><em>7.96 Ω.</em>
<u>Solution-</u>
Two capacitors, a 20 mF and a 30 mF, are connected in parallel to a 400 Hz source.
The effective/equivalent capacitance of the circuit is,
As, when capacitors are connected together in parallel, the equivalent capacitance in the circuit is equal to the sum of capacitance of all the individual capacitor.
We know that,
Where,
= Capacitive Reactance (in Ω)
f = frequency (in Hz)
C = Capacitance (in F)
Here given,
= ??
f = 400 Hz
C = 50 mF = F
Putting the values in the formula,
Therefore, the total capacitive reactance of the circuit is 7.96 Ω.
Answer:
<em>The numbers between -5 and 5</em>
Step-by-step explanation:
Intersection of Intervals
Given the intervals A,B,C,etc. The intersection of them all is the set of all values that are common to all the intervals.
We must find
which is the intersection between the intervals x > -5 and x < 5. The intersection represents all the numbers greater than -5 and less than 5. It can also be said The numbers between -5 and 5 (non inclusive), third option