Find the zeros of the function f(x) = 1/3 x^2 + 72
1 answer:
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First box
<em>4/10</em>
0.4 divided by 1
0.4/1 *10
= 4/10
Box on top that's the point where it's 3 away from 4/10
<em>0.7</em>
Bottom
<em>7/10</em>
<em />
0.7 divided by 1
0.7/1*10
= 7/10
Next box
<em>0.9</em>
9/10
= 0.9
Answer:
Option C.
Step-by-step explanation:
As we can see from the graph, we have plotted the different points.
If the line drawn through the scatter plots, shows the relationship between the length x and mass f(x) then the function will be in the form of
f(x) = mx + b
where m = slope of the line that fits the best
b = y-intercept of the line
Since the plotted line passes through two pints (1, 1) and (10, 94).
Then the slope m =
m =
m =
m = 10.3
Now we place the coordinates (1, 1) in the equation to find the value of y-intercept b.
1 = 10.3 + b
b = 1 - 10.3
b = -9.3 ≈ 9
So the function will be f(x) = 10.3x - 9
Option C is the answer.
