Answer:
4 * 8 * 6 = 192
Explanation:
First menu = 4 selections
second menu = 8 selections
third menu = 6 selections
we need to find how many configuration can the game be played, we just here multiply all the selections and find the answer
4 * 8 * 6 = 192
you distribute and then combine like terms. x=4 :))
Answer:
This code will print: 4
Explanation:
Following is the step-by-step explanation for the given code:
- Given is the array of data type double named myList, it has entries, 1, 5, 5, 5,5, 1:
double[] myList = {1, 5, 5, 5, 5, 1};
- Now the first element of the array (1) with index 0 will be stored in the variable max (data type double).
double max = myList[0];
- A variable indexOfMax having datatype int will be initiated as 0.
int indexOfMax = 0;
- Now for loop will be used to find the maximum number of the array. The variable i will be put as index for each element to compare with first element. If the checked element is greater than or equal to the integer in max, it will be replaced. So at the end the variable max will have value 5 that will be at index i = 4.
for (int i = 1; i < myList.length; i++)
{ if (myList[i] >= max)
{ max = myList[i];
- Now the variable i that is the index for max value will be stored in the variable indexOfMax (indexOfMax = 4).
indexOfMax = i; }}
- At end the value stored in variable indexOfMax will be printed, so 4 will be printed as output.
System.out.println(indexOfMax);
i hope it will help you!
<span>In the process of 5B/6B encoding, it is possible to have the following two kinds of data sequences: 1. 25=32 data sequences 2. 26=64 data sequences Therefore, this can left us with some unused code sequences that are 32 in number (=26 – 25). On the other hand, in the encoding process of 3B/4B, it is possible to another set of data sequences as follows: 1. 23=8 data sequences 2. 24=16 data sequences This type of encoding also leaves us with some unused code sequences that are 8 in number (=23-24). 2. </span>
Im not quite sure but i got mine back yesterday soooo (pretty good)
