Answer:
Java Class given below
Explanation:
class ReadOnly
{
protected int val;
public ReadOnly(int arg)
{
val = arg;
}
public int getVal()
{
return val;
}
}
class ReadWrite extends ReadOnly
{
private boolean dirty;
public ReadWrite(int arg)
{
super(arg);
dirty = false;
}
public void setVal(int arg)
{
val = arg;
dirty = true;
}
public boolean isDirty()
{
return dirty;
}
}
The answer to your question is true.
Answer:
Answered below
Explanation:
class TestScores {
double test1;
double test2;
double test 3;
public TestScores (double test1, double test2, double teat3){
this.test1= test1;
this.test2 = test2;
this.test3 = teat3;}
//mutator
public setTest1(double test1){
this.test1 = test1;
}
//accessor
public double getTest1(){
return test 1;
}
//Write same accessors and mutators for test2 and test3
public double getTestAverage(){
double sum = test1+test2+test3;
return sum / 3;
}
}
class TestRun{
public static void main (String [] args){
TestScores scores = new TestScores(50.5, 40.0, 80.7)
int average = scores.getTestAverage();
System.out.print(average);
}
Answer:
B. {1, 2, 2, 3, 3, 4, 5}
Explanation:
Given
The above code segment
Required
Determine which list does not work
The list that didn't work is 
Considering options (A) to (E), we notice that only list B has consecutive duplicate numbers i.e. 2,2 and 3,3
All other list do not have consecutive duplicate numbers
Option B can be represented as:
![nums[0] = 1](https://tex.z-dn.net/?f=nums%5B0%5D%20%3D%201)
![nums[1] = 2](https://tex.z-dn.net/?f=nums%5B1%5D%20%3D%202)
![nums[2] = 2](https://tex.z-dn.net/?f=nums%5B2%5D%20%3D%202)
![nums[3] = 3](https://tex.z-dn.net/?f=nums%5B3%5D%20%3D%203)
![nums[4] = 3](https://tex.z-dn.net/?f=nums%5B4%5D%20%3D%203)
![nums[5] = 4](https://tex.z-dn.net/?f=nums%5B5%5D%20%3D%204)
![nums[6] = 5](https://tex.z-dn.net/?f=nums%5B6%5D%20%3D%205)
if (nums.get(j).equals(nums.get(j + 1)))
The above if condition checks for duplicate numbers.
In (B), when the elements at index 1 and 2 (i.e. 2 and 2) are compared, one of the 2's is removed and the Arraylist becomes:
![nums[0] = 1](https://tex.z-dn.net/?f=nums%5B0%5D%20%3D%201)
![nums[1] = 2](https://tex.z-dn.net/?f=nums%5B1%5D%20%3D%202)
![nums[2] = 3](https://tex.z-dn.net/?f=nums%5B2%5D%20%3D%203)
![nums[3] = 3](https://tex.z-dn.net/?f=nums%5B3%5D%20%3D%203)
![nums[4] = 4](https://tex.z-dn.net/?f=nums%5B4%5D%20%3D%204)
![nums[5] = 5](https://tex.z-dn.net/?f=nums%5B5%5D%20%3D%205)
The next comparison is: index 3 and 4. Meaning that comparison of index 2 and 3 has been skipped.
<em>This is so because of the way the if statement is constructed.</em>
Answer:
(GUI) stands for Graphical User Interface