Hurry I'm TIMED!!!! The following graph shows the low temperatures for the past six nights. What was the range of temperatures f
2 answers:
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You must try to remove one of the unknown variables from the system by multiplying one in a way that when adding (or subtracting) one to another “makes it disappear” and so whatever value you get can be substituted back in to get the other unknown!
The value of h(t) when is 10.02.
Solution:
Given function
To find the value of h(t) when :
Substitute in the given function.
Now multiply the common terms into inside the bracket.
Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.
To make the denominator same, take LCM of the denominators.
LCM of 64 and 32 = 64
= 10.02
Hence the value of h(t) when is 10.02.