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yaroslaw [1]
3 years ago
10

Using an applet, we found that the theory-based test results in a t-statistic of -7.25 and p-value less than 0.0001. State your

conclusion in the context of the study.
a. We have very strong evidence that the long-run average guess of the population size of Milwaukee, Wisconsin is smaller with the anchor of Chicago than with the anchor of Green Bay.
b. We have very strong evidence that the long-run average guess of the population size of Milwaukee, Wisconsin is smaller with the anchor of Green Bay than with the anchor of Chicago.
c. We have very weak evidence that the long-run average guess of the population size of Milwaukee, Wisconsin is larger with the anchor of Green Bay than with the anchor of Chicago.
d. We have very weak evidence that the long-run average guess of the population size of Milwaukee, Wisconsin is larger with the anchor of Chicago than with the anchor of Green Bay.
Mathematics
1 answer:
11111nata11111 [884]3 years ago
7 0

Answer:

b. We have very strong evidence that the long-run average guess of the population size of Milwaukee, Wisconsin is smaller with the anchor of Green Bay than with the anchor of Chicago.

Step-by-step explanation:

Smaller p-value indicates a strong evidence in favor of the alternative hypothesis which means we can reject the null hypothesis. In the given scenario the p-value is 0.0001 which is very small. There is sufficient evidence for the rejection of null hypothesis.

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The ratio of the perimeter of square RSTU to the perimeter of square WXYZ is 1 to 2. The area of square RSTU is 81 square inches
Vlad1618 [11]
The answer would be 25.5 inches.
4 0
3 years ago
Please help me with this question! :)
RSB [31]

Answer:

red is the anwser y=3x+2

6 0
3 years ago
A rectangle has a length that is 5 inches more than the width Its perimeter is 50 inches. Find the length
Crazy boy [7]

Answer:

Length is 30 width is 20

Step-by-step explanation:

50 divided 2 is 25. Add 5 to 25. Then you have two parts. 30 and 20.

They are your answers.

4 0
3 years ago
Question A volleyball team sold raffle tickets to raise money for the upcoming season. They sold three different types of ticket
m_a_m_a [10]

Answer:

24 premium tickets were sold.

Step-by-step explanation:

Let :

Deluxe ticket = x

Regular tickets = x + 78

Premium tickets = y

x + (x + 78) + y = 208

4x + 2(x+78) + 10y = 714

2x + y = 208 - 78

4x + 2x + 156 + 10y = 714

2x + y = 130 - - - - - (1)

6x + 10y = 558 - - - - (2)

Now we can solve the simultaneous equation using elimination method :

From (1)

y = 130 - 2x

Put y = 130 - 2x in (2)

6x + 10(130 - 2x) = 558

6x + 1300 - 20x = 558

- 14x = 558 - 1300

-14x = - 742

x = 742 / 14

x = 53

Put x = 53 in y = 130 - 2x

y = 130 - 2(53)

y = 130 - 106

y = 24

3 0
2 years ago
Order the situations from the account that yields the greatest amount to one that yields the least amount.
Bumek [7]

Answer:

Order from the greatest yield to the least as follows

1. Situation B=$2,119.8949

2. Situation A=$2,095.3078

3. Situation C=$2,022.7789

Step-by-step explanation:

Situation A

A=P(1+r/n)^nt

=500(1+0.12/12)^12*12

=500(1+0.01)^144

=500(1.01)^144

=500(4.1906155936008)

=$2,095.3078

Situation B

A=P(1+r/n)^nt

=500(1+0.1/4)^4*15

=500(1+0.025)^60

=500(1.025)^60

=500(4.3997897488150)

=$2119.8949

Situation C

A=P(1+r)^t

=500(1+0.15)^10

=500(1.15)^10

=500(4.0455577357079)

=$2022.7789

Order from the greatest yield to the least as follows

1. Situation B=$2,119.8949

2. Situation A=$2,095.3078

3. Situation C=$2,022.7789

5 0
3 years ago
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