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2 years ago

Determine a polynomial that represents the area of the parallelogram. A=

Mathematics

1 answer:

sp2606 [1]2 years ago

6 0

Answer:

4b² - 16

Step-by-step explanation:

The formula to find the area of a parallelogram equals $bh$ , where b = base and h - height. We're given the base as 2b + 4 and the height as 2b - 4.

$(2b+4)*(2b-4)=(2b+4)(2b-4)$
$(2b+4)(2b-4)=(2b)(2b)+(2b)(-4)+(4)(2b)+(4)(-4)$
$4b^2-8b+8b-16$
$4b^2-16$

Therefore, the answer is 4b² - 16.

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Answer:

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Step-by-step explanation:

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Taking LHS of the above expression

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Rationalizing both denominator and numerator.

$\dfrac{2-\sqrt5}{2+3\sqrt5}\times \dfrac{2-3\sqrt5}{2-3\sqrt5}=\dfrac{4-6\sqrt5-2\sqrt5+15}{2^2-(3\sqrt5)^2}\\\\=\dfrac{19-8\sqrt5}{4-45}\\\\=\dfrac{19-8\sqrt5}{-41}\\\\=\dfrac{\sqrt5 \times 8}{41}+(\dfrac{-19}{41})$

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