Theorem: If two chords intersect within a circle, then the product of the lengths of the segments (parts) of one chord is equal to the product of the lengths of the segments of the other chord.
This means that
If PA=PB, then subtituting PA instead of PB in previous equality you get
Answer: true.
The product of the sum of two perfect cubes:
a³ + b³ = (a + b)(a² - ab + b²)
The product of the difference of two perfect cubes:
a³ - b³ = (a - b)(a² + ab + b²)
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Remember to follow FOIL:
(b^2 + 8)(b^2 - 8)
(b^2)(b^2) = b^4
(b^2)(-8) = -8b^2
(8)(b^2) = 8b^2
(8)(-8) = -64
b^4 - 8b^2 + 8b^2 - 64
Combine like terms:
b^4 (-8b^2 + 8b^2) - 64
b^4 - 64
b^4 - 64 is your answer
hope this helps
Answer:
47.80
Step-by-step explanation:
jejjdbdiehejee
Answer:
Since YS is an angle bisector, ∠XYS=∠SYZ
∠SYZ= 34.2°
∠XYZ= 34.2+34.2=68.4°
Step-by-step explanation:
