Given:
7 red candies
9 blue candies
12 pink candies
Condition:
Number of bags that has equal number of candies.
We can do 7 bags with 1 colored candy each. There will be an excess of 2 blue candies and 5 pink candies.
We can do 4 bags with 1 red candy, 2 blue candies, 3 pink candies. There will be an excess of 3 red candies and 1 blue candy.
We can do 3 bags with 2 red candies, 3 blue candies, 4 pink candies. There will be an excess of 1 red candy.
Answer:
All 3 are right triangles.
Step-by-step explanation:
In a right triangle c^2 = a^2 + b^2 where c is the longest side. ( by Pythagoras).
a) 3^2 = 9, 6^2 = 36 and √27 ^ 2 = 27
36 = 9 + 27
So this is a right triangle.
b)
17^2 = 289, 15^2 = 225 and 8^2 = 64
289 = 225 + 64
Also right triangle.
c) √50 ^ 2 = 50, 5^2 = 25 and 5^2 = 25
So also right triangle.
P = 2 × 4in + 2 × 1in = 8in + 2in = 10in
<h2><u>
P = 10 in</u></h2>
-1 - (-7) = 6
5 - (-1) = 6
11 - 5 = 6
The common difference is 6.
If you add 6 to a term, you get the next term.
Answer:
distribute parenthesis
Step-by-step explanation:
6(2x + 1) = 4x - 5 ← distribute parenthesis on left side
12x + 6 = 4x - 5 ( subtract 4x from both sides )
8x + 6 = - 5 ( subtract 6 from both sides )
8x = - 11 ( divide both sides by 8 )
x = - 
