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3 years ago

7

Diana is walking at 5 miles per hour and Gustavo is walking at 6 miles per hour and started 1 mile behind Diana. Will Gustavo ev

er catch up and if so after how many hours?

2 answers:

ziro4ka [17]3 years ago

8 0

Yes he will catch up

Andrews [41]3 years ago

7 0

Yes he will because he is walking 6 miles per hour which is greater than 5 so he will catch up hope this helps ;:[];

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A beaker contains 0.5 liter of solution.Jordan uses 0.08 of the solution for an experiment.How much of the solution does Jordan

schepotkina [342]

I feel like this is a trick question

In the question it states "Jordan uses 0.08 of the solution for an experiment"

Which means that the answer is 0.08. Jordan uses 0.08 of the solution

5 0

3 years ago

Int he figure below find AC

Ahat [919]

Given :-

Two triangles with their two angles equal .

To Find :-

Measure of AC .

Answer :-

Here in ∆ABC and ∆EDC ,

$\angle$ CAB = $\angle$ CED (given )
$\angle$ CBA = $\angle$ CDE (given)

Therefore by AA similarity criterion , we can say that ∆ABC ~ ∆EDC . Also we know that corresponding sides of similar triangles are proportional . So ,

→ AC/EC = BC/DC

→ AC/9 = 8/12

→ AC = 8/12 * 9

→ AC = 6

<u>Hence</u><u> the</u><u> </u><u>measure</u><u> of</u><u> </u><u>side </u><u>AC </u><u>is </u><u>6</u><u> </u><u>.</u>

I hope this helps.

7 0

2 years ago

PLEASE HELP, I'LL MARK BRAINLY (EASY)!

vfiekz [6]

For 1. The answer is “x = 4”
Explanation: 5 X 4 = 20 and 4 - 3 = 1
By adding all equal sides together the sum is 42 so x is 4

5 0

2 years ago

You earn $12.50 an hour at your job. How many hours do you need to work to<br> make more than $425?

Harman [31]

37 hours
$425/$12.50= 36.16
rounded= 37

4 0

2 years ago

Read 2 more answers

Someone please help with parts a b c and d. I will mark brainlest!!!

maria [59]

Answer:

A. 49 feet

B. 66 feet (round to the nearest foot)

C. 4 seg

Step-by-step explanation:

A. What is the height of the ball after 3 seconds?

For $t=3 seg$

$h(3)=-16(3)^{2} +63(3)+4$

$h(3)=-144+189+4\\h(3)=-144+193\\h(3)=49 feet$

B. What is the maximum height of the ball? round to the nearest foot

$h(t)=-16(t)^{2} +63(t)+4\\h'(t)=-32(t) +63\\$

then

$-32(t)+63=0\\t=\frac{-63}{-32}\\t=1.969seg$

For $t=1.969seg$

$h(1.969)=-16(1.969)^{2}+63(1.969)+4\\h(1.969)= 66.016\\h(1.969)=66 feet$

C. When will the ball hit the ground?

The ball will hit the ground when $h(t)=0$

so, $-16t^{2} +63(t)+4=0$

Using the quadratic equation

$t=4seg$

6 0

3 years ago