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Ganezh [65]
1 year ago
7

The sum of two numbers is 32. One number is 3 times as large as the other. What are the numbers?

Mathematics
1 answer:
ANTONII [103]1 year ago
4 0

Answer: 8, 24

Step-by-step explanation:

Since the sum of two numbers is 32 and one number is 3 times as large as the other, the first number can be defined as x and the second number is 3x.

Divide 32 by (3+1) = 4 and you get 8, which is x.

The second number is 3(8) = 24.

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Question 1,2, and 3 how do i factor those? Can you show the work and explain how?
DiKsa [7]

1: 3n^{2}+9n+6

notice that each part is divisible by 3

3n^{2} ÷ 3 = n^{2}

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes 3(n^{2} +3n+2)

3n can be rewritten as 2n+n

-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

3(n^{2} +2n+n+2)

Now that it's rewritten, you can factor out n + 2 from the equation.

<u><em>the answer is </em></u>

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is n^{2} +2n+n+2 and then each of those by 3, which is 3n^{2} +6n+3n+6 or 3n^{2}+9n+6, our origional equation

2: 28+x^{2} -11x

So I rewrote this as x^{2} -11x+28 (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

(remember, the two numbers should multiply to equal 28, which is our constant.)

x^{2} -4x-7x+28

now we can factor out x from the first expression and -7 from the second

x(x-4)-7(x-4)

and lastly you factor out x-4,

<u><em>which would give you</em></u>

(x-4)(x-7)

Make sure to check your work and make sure it multiplies to x^{2} -11x+28

3: 9x^{2} -12x+4

The first thing I notice when looking at this problem is that both 9 and 4 are perfect squares. Not only that, but they are the squares of 2 and 3, which are products of -12

So if you rewrite 9 as 3^{2} and 4 as 2^{2}, the equation becomes

3^{2} x^{2} -12x+2^{2}

now that 3^{2} x^{2} is ugly so it can be turned into (3x)^{2}

and -12x can be rewritten as -2*3x*2

so our equation now looks like (3x)^2-2*3x*2+2^{2}

There's a rule that says a^{2} -2ab+b^{2} = (a-b)^{2}

In our case, a=3x and b=2

<u><em>so the final answer is</em></u>

(3x-2)^2

5 0
2 years ago
The distance from the origin to the point ​(-24​, 32​) is
Zepler [3.9K]
The Pythagorean theorem tells you that distance is
.. √((-24)^2 +32^2)) = √(576 +1024) = √1600 = 40
6 0
3 years ago
What is -9 times 4/3<br><br> In simplest form
andre [41]
-9/1*4/3=-36/3
-36/3 is known as -12. The answer is -12.

8 0
2 years ago
Read 2 more answers
Endpoint: (1,7), midpoint: (-10,10)
algol [13]

The answer is (-21, 13) for The second endpoint.  

Let's start by calling the known endpoint L and the unknown K. We'll call the midpoint M. In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.

(Kx + Lx)/2 = Mx

(Kx + 1)/2 = -10

Kx + 1 = -20

Kx = -21

And now we do the same thing for y values

(Ky + Ly)/2 = My

(Ky + 7)/2 = 10

Ky + 7 = 20

Ky = 13

This gives us the final point of (-21, 13)

5 0
3 years ago
Whats 2099 dived by 800
sergejj [24]

Answer:

2099/800= 2.62375

Step-by-step explanation:

5 0
2 years ago
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