Answer:
The travel time that separates the top 2.5% of the travel times from the rest is of 91.76 seconds.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 80 seconds and a standard deviation of 6 seconds.
This means that 
What travel time separates the top 2.5% of the travel times from the rest?
This is the 100 - 2.5 = 97.5th percentile, which is X when Z has a p-value of 0.975, so X when Z = 1.96.




The travel time that separates the top 2.5% of the travel times from the rest is of 91.76 seconds.
Answer:
2/15 servings
Step-by-step explanation:
IF a basket contains 15/16 pound of oranges, then;
1 servings= 15/16 pounds of oranges
To get the number of servings for 1/8 pounds
x servings = 1/8 pounds
Divide both expressions
1/x = (15/16)/(1/8)
1/x = 15/16 * 8/1
1/x = 15/2
x = 2/15
Hence there will be 2/15 servings of oranges
Four sided figure is a quadrilateral
Answer:
The answer is C
Step-by-step explanation:
did the test on edg
Your answer is d. hope this helps