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Reika [66]
4 years ago
15

Determine the first five terms of the sequence whose nth term is defined as follows. Please enter the five terms in the

Mathematics
1 answer:
katen-ka-za [31]4 years ago
5 0
If the question is what is 3n-6
Then the answer is 3(n-2)
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One number is 876.2 more than twice the other. If the sum of the two numbers is 2005.46, find the larger of the two numbers?
kirza4 [7]

Answer:

these .56 because they are bigger

Step-by-step explanation:

hope this helps

4 0
2 years ago
Sin(4x) in the term of just x<br> Please help!!
Nina [5.8K]

I think you mean in terms of \sin(x)?

Recall Euler's identity

e^{ix} = \cos(x) + i \sin(x)

and de Moivre's theorem

\left(e^{ix}\right)^n = \left(\cos(x) + i \sin(x)\right)^n = \cos(nx) + i \sin(nx) = e^{inx}

where i=\sqrt{-1}.

It follows that

\sin(4x) = \mathrm{Im}\left(\cos(x) + i \sin(x)\right)^4

By the binomial theorem, expanding the right side gives

\cos^4(x) + 4i \cos^3(x) \sin(x) - 6\cos^2(x) \sin^2(x) - 4i \cos(x) \sin^3(x) + \sin^4(x)

and so

\sin(4x) = 4\cos^3(x) \sin(x) - 4 \cos(x) \sin^3(x)

We can factorize this as

\sin(4x) = 4 \cos(x) \sin(x) \left(\cos^2(x) - \sin^2(x)\right)

and using the Pythagorean identity

\cos^2(x)+\sin^2(x) = 1 \implies \cos(x) = \pm \sqrt{1-\sin^2(x)}

this reduces to

\sin(4x) = \pm 4 \sqrt{1-\sin^2(x)} \sin(x) (1 - 2 \sin^2(x))

8 0
2 years ago
Which is the process by which gas exchange between the respiratory system and the blood cells in the cappilaries occurs? transfu
Oksi-84 [34.3K]

Answer:

diffusion

Step-by-step explanation:

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6 0
3 years ago
Draw a model to find the product 24 times 84
Nadya [2.5K]
The product of 24 and 84 is 2016.
5 0
3 years ago
Read 2 more answers
Solve rational Equation <br><br> Please Show Full Steps Please!
pochemuha

Answer:

x=1

Step-by-step

Step 1:

Simplify x/x2

Dividing exponential expressions :  

1.1    x1 divided by x2 = x(1 - 2) = x(-1) = 1/x1 = 1/

Equation at the end of step 1:

  2    1         1

 (((—+1)-—)-1)-((2•—)-1)  = 0

    x    x         x

STEP 2:Rewriting the whole as an Equivalent Fraction:

2.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  x  as the denominator :

        1     1 • x

   1 =  —  =  —————

        1       x  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

2 - (x)     2 - x

——— = ———  

   x          x  

Equation at the end of step 2:

2    1     (2-x)

 (((—+1)-—)-1)-—————  = 0

    x    x       x  

STEP 3:

Simplify 1/x

Equation at the end of step 3:

2          1           (2 - x)

 (((— +  1) -  —) -  1) -  ———————  = 0

    x          x              x  

STEP4:

Simplify: 2/x

Equation at the end of step 4:

    2          1                 (2 - x)

 (((— +  1) -  —) -  1) -  ———————  = 0

    x          x                      x  

STEP 5:

Rewriting the whole as an Equivalent Fraction :

5.1   Adding a whole to a fraction

Rewrite the whole as a fraction using  x  as the denominator :

        1         1 • x

   1 =  —  =  —————

        1            x  

Adding fractions that have a common denominator :

5.2       Adding up the two equivalent fractions

2 + x                x + 2

—————  =  —————

  x                       x  

Equation at the end of step 5:

(x + 2)    1                                (2 - x)

 ((——————— -  —) -  1) -  ———————  = 0

      x       x                                  x  

STEP 6:Adding fractions which have a common denominator :

Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

(x+2) - (1)                            x + 1

———————————  =  —————

     x                                       x

Equation at the end of step 6:

  (x + 1)                           (2 - x)

 (——————— -  1) -  ———————  = 0

     x                               x

STEP 7:

Rewriting the whole as an Equivalent Fraction :

7.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  x  as the denominator :

        1     1 • x

   1 =  —  =  —————

        1       x  

Adding fractions that have a common denominator :

7.2       Adding up the two equivalent fractions

(x+1) - (x)                           1

———————————  =  —

     x                                   x

Equation at the end of step 7:

 1       (2 - x)

 — -  ———————  = 0

 x         x

STEP 8:

Adding fractions which have a common denominator :

8.1       Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

1 - ((2-x))                              x - 1

———————————  =  —————

     x                                     x    

Equation at the end of step 8:

 x - 1

 —————  = 0

   x  

STEP 9:

When a fraction equals zero :

9.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 x-1

 ——— • x = 0 • x

  x

Now, on the left hand side, the  x  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  x-1  = 0

.2      Solve  :    x-1 = 0

Add  1  to both sides of the equation :

                     x = 1

One solution was found :

x = 1

   

8 0
3 years ago
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