Answer:
Step-by-step explanation:
Yes.
Based on the measurements of the pool and the path of uniform width, the area of the width and length of the path can be found to be 28.8 meters.
<h3>How to find the width and length?</h3>
First, find the area of the pool:
= Length x Width
= 10 x 26
= 260 meters ²
The area of the path can therefore be found to be:
= Total area of pool and path combined - Area of pool
= 1,092 - 260
= 832 meters²
Seeing as the path has uniform width, that means that the width is the same and the length so the width and length of the pool is:
= √area of the path
= √832
= 28.8
In conclusion, the width and length of the path are 28.8 meters.
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Answer:
The solution to the system of equations are;
x = -4/3
y = 5/3
Step-by-step explanation:
To find the Solution, we would carry the Operation simultaneously.
4x + 2 = -2y .........(i)
6y - 18 = 6x ..........(ii)
First let's rearrange the equations, to make the journey smoother
2y + 4x = -2 ...........(iii)
6y - 6x = 18 ...........(iv)
Let's Multiply equation (III) by 3 so as to have a uniform spot to begin elimination.
3.2y + 3.4x = -2 . 3
6y + 12x = -6............... (v)
Let's subtract equation (v) from equation (iv)
= 0y - 18x = 24
-18x = 24
x = - 24 / 18
x = -4/3
Let's substitute (x = -4/3) in equation (ii), so that we can solve for the value of y:
6y - 18 = 6x
6y - 18 = 6 (-4/3)
6y - 18 = -8
6y = -8 + 18
6y = 10.
y = 10 / 6
y = 5/3
The solution to the system of equations are;
x = -4/3
y = 5/3
