A sample with mean of 85 and SD of 12 is transformed into z-scores. After the transformation, what are the values for the mean a
nd standard deviation for the sample of z-scores
1 answer:
Answer:
The value remain unchanged.
Step-by-step explanation:
By Z score, we mean:
Z = 
, if we substitute the given values of mean and standard deviation, we obtain the z score value. That is,
Z = 
= 85/12 = 7.083333.
NB: We assume that mean and standard deviation are in the same units.
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Step-by-step explanation:
The lines that intersect is B
A) $15 ÷ 40% =
15×.4= 6
15+6= 21
B) $38 × .25=9.5
38-9.5=28.50
28.50×.06=1.71
28.50+1.17=30.21
I think this is how you do it. would wait for other answers as well to double check.
12300=X[((1-(1+(0.072/12)^(-12*8))/(0.072/12)]
Solve for x
X=168.92
Answer:
B
Step-by-step explanation:
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