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ss7ja [257]
2 years ago
11

m{Simplify:-}}" alt=" \displaystyle{ \rm{Simplify:-}}" align="absmiddle" class="latex-formula">
2 1/2×14/25÷{2/5÷(4/7-1/2)}​
Mathematics
2 answers:
fenix001 [56]2 years ago
5 0

\frac{1}{4} is the answer.

(<em>I </em><em>have </em><em>included </em><em>the</em><em> </em><em>answer </em><em>as </em><em>picture</em><em>.</em><em>)</em>

\rm{Have \: a \: great \: day! \: :)}

zvonat [6]2 years ago
4 0

Answer:

\rm{hope \: thisss \: helpssss \: youuuuu.....}

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Leslie used 20% of a half-gallon (64 ounces) of milk for a recipe. How many ounces of milk were left?
Lady_Fox [76]

Answer:

51.2 ounces.

Step-by-step explanation:

If its 20% of a 64 ounce half gallon, you just need to find the last 80% of the half gallon. Since you know it is 64 ounces you can divide it by 5 which gives you 12.8. 12.8 would be 20% so you just subtract 12.8 from 64 ounces which gives you 51.2.

5 0
3 years ago
y=c1e^x+c2e^−x is a two-parameter family of solutions of the second order differential equation y′′−y=0. Find a solution of the
vagabundo [1.1K]

The general form of a solution of the differential equation is already provided for us:

y(x) = c_1 \textrm{e}^x + c_2\textrm{e}^{-x},

where c_1, c_2 \in \mathbb{R}. We now want to find a solution y such that y(-1)=3 and y'(-1)=-3. Therefore, all we need to do is find the constants c_1 and c_2 that satisfy the initial conditions. For the first condition, we have:y(-1)=3 \iff c_1 \textrm{e}^{-1} + c_2 \textrm{e}^{-(-1)} = 3 \iff c_1\textrm{e}^{-1} + c_2\textrm{e} = 3.

For the second condition, we need to find the derivative y' first. In this case, we have:

y'(x) = \left(c_1\textrm{e}^x + c_2\textrm{e}^{-x}\right)' = c_1\textrm{e}^x - c_2\textrm{e}^{-x}.

Therefore:

y'(-1) = -3 \iff c_1\textrm{e}^{-1} - c_2\textrm{e}^{-(-1)} = -3 \iff c_1\textrm{e}^{-1} - c_2\textrm{e} = -3.

This means that we must solve the following system of equations:

\begin{cases}c_1\textrm{e}^{-1} + c_2\textrm{e} = 3 \\ c_1\textrm{e}^{-1} - c_2\textrm{e} = -3\end{cases}.

If we add the equations above, we get:

\left(c_1\textrm{e}^{-1} + c_2\textrm{e}\right) + \left(c_1\textrm{e}^{-1} - c_2\textrm{e}  \right) = 3-3 \iff 2c_1\textrm{e}^{-1} = 0 \iff c_1 = 0.

If we now substitute c_1 = 0 into either of the equations in the system, we get:

c_2 \textrm{e} = 3 \iff c_2 = \dfrac{3}{\textrm{e}} = 3\textrm{e}^{-1.}

This means that the solution obeying the initial conditions is:

\boxed{y(x) = 3\textrm{e}^{-1} \times \textrm{e}^{-x} = 3\textrm{e}^{-x-1}}.

Indeed, we can see that:

y(-1) = 3\textrm{e}^{-(-1) -1} = 3\textrm{e}^{1-1} = 3\textrm{e}^0 = 3

y'(x) =-3\textrm{e}^{-x-1} \implies y'(-1) = -3\textrm{e}^{-(-1)-1} = -3\textrm{e}^{1-1} = -3\textrm{e}^0 = -3,

which do correspond to the desired initial conditions.

3 0
3 years ago
Write these decimal fractions in words 42/100
hodyreva [135]
Forty two over one hundred 
7 0
3 years ago
Read 2 more answers
6 x 10^4 please help me I just don’t want to do the math right now I’m so tired
mote1985 [20]

Answer:

6,000

Step-by-step explanation:

7 0
3 years ago
30 girls and boys have planned for a picnic. there is a ratio of 3 girls to 7 boys how many boys are there?
adell [148]
To solve the given problem We can consider, 30% are girls of 30 people 70% are boys in 30 people In order to get the number, we just multiply the total number of people with the percentage of the designated target populace.
<span><span>1.    </span>30 x 0.3 = 9 girls</span> <span><span>
2.    </span>30 x 0.7 = 21 boys</span> <span><span>
3.    </span>21 boys + 9 girls = 30 people</span>

Hence, there are 21 boys.



4 0
3 years ago
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