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3 years ago

8

floodwalls are used to prevent damage from floods. A town built a floodwall 4 4/8 feet tall. Another town built a floodwall 7 1/

8 feet tall. what is the difference between the height of the floodwalls

1 answer:

Bas_tet [7]3 years ago

7 0

Answer:3 3/8

Step-by-step explanation:

Im not sure but im not dumb good luck

just minus 4 from 7 = 3 and 1-4=3

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astra-53 [7]

Answer:

<h2>Net proceed= s-0.98nd-11</h2>

Step-by-step explanation:

Given that the shares cost $d

n shares will be =$dn

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Net proceed= s-(nd-0.02nd)-11

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2 years ago

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Answer:

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2 years ago

Dividing integers

Natasha2012 [34]

<em>first we shall learn the rules.when numbers with same sign are divided it gives pisitive sign but, when numbers of different signs are divided it gives negetive sign.</em>

<em>first we shall learn the rules.when numbers with same sign are divided it gives pisitive sign but, when numbers of different signs are divided it gives negetive sign.here,</em>

<em>first we shall learn the rules.when numbers with same sign are divided it gives pisitive sign but, when numbers of different signs are divided it gives negetive sign.here,7. (-154) ➗ (-14) =11</em>

<em>first we shall learn the rules.when numbers with same sign are divided it gives pisitive sign but, when numbers of different signs are divided it gives negetive sign.here,7. (-154) ➗ (-14) =1111. (-40) ➗10=-4</em>

<em>first we shall learn the rules.when numbers with same sign are divided it gives pisitive sign but, when numbers of different signs are divided it gives negetive sign.here,7. (-154) ➗ (-14) =1111. (-40) ➗10=-415. 90 ➗ (-15)=-6</em>

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<em>first we shall learn the rules.when numbers with same sign are divided it gives pisitive sign but, when numbers of different signs are divided it gives negetive sign.here,7. (-154) ➗ (-14) =1111. (-40) ➗10=-415. 90 ➗ (-15)=-616. 108 ➗ (-9)=-1217. (-48) ➗ (-6)=818. (-105) ➗ 7=-15</em>

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8 0

3 years ago

DiKsa [7]

Answer:

See Below.

Step-by-step explanation:

Problem 1)

We want to simplify:

$\displaystyle \frac{a+2}{a^2+a-2}+\frac{3}{a^2-1}$

First, let's factor the denominators of each term. For the second term, we can use the difference of two squares. Hence:

$\displaystyle =\frac{a+2}{(a+2)(a-1)}+\frac{3}{(a+1)(a-1)}$

Now, create a common denominator. To do this, we can multiply the first term by (<em>a</em> + 1) and the second term by (<em>a</em> + 2). Hence:

$\displaystyle =\frac{(a+2)(a+1)}{(a+2)(a-1)(a+1)}+\frac{3(a+2)}{(a+2)(a-1)(a+1)}$

Add the fractions:

$\displaystyle =\frac{(a+2)(a+1)+3(a+2)}{(a+2)(a-1)(a+1)}$

Factor:

$\displaystyle =\frac{(a+2)((a+1)+3)}{(a+2)(a-1)(a+1)}$

Simplify:

$\displaystyle =\frac{a+4}{(a-1)(a+1)}$

We can expand. Therefore:

$\displaystyle =\frac{a+4}{a^2-1}$

Problem 2)

We want to simplify:

$\displaystyle \frac{1}{(a-b)(b-c)}+\frac{1}{(c-b)(a-c)}$

Again, let's create a common denominator. First, let's factor out a negative from the second term:

$\displaystyle \begin{aligned} \displaystyle &= \frac{1}{(a-b)(b-c)}+\frac{1}{(-(b-c))(a-c)}\\\\&=\displaystyle \frac{1}{(a-b)(b-c)}-\frac{1}{(b-c)(a-c)}\\\end{aligned}$

Now to create a common denominator, we can multiply the first term by (<em>a</em> - <em>c</em>) and the second term by (<em>a</em> - <em>b</em>). Hence:

$\displaystyle =\frac{(a-c)}{(a-b)(b-c)(a-c)}-\frac{(a-b)}{(a-b)(b-c)(a-c)}$

Subtract the fractions:

$\displaystyle =\frac{(a-c)-(a-b)}{(a-b)(b-c)(a-c)}$

Distribute and simplify:

$\displaystyle =\frac{a-c-a+b}{(a-b)(b-c)(a-c)}=\frac{b-c}{(a-b)(b-c)(a-c)}$

Cancel. Hence:

$\displaystyle =\frac{1}{(a-b)(a-c)}$

4 0

3 years ago

Is 0.258 a rational number?

MrRissso [65]

Answer:

Step-by-step explanation:

Yes it is a rational number

5 0

2 years ago