Question

The nth term of a sequence is 4n^2 -n-1. What is the 11th term of the sequences?

Answer 1

Answer:

The 11th term is 472

Step-by-step explanation:

$t_{n} = 4 {n}^{2} - n - 1$

$t_{11} = 4 \times {11}^{2} - 11 - 1$

$= 4 \times 121 - 12 \\ = 484 - 12 \\ = 472$