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3 years ago

10

it takes you 45 minutes to drive the 30 miles from your house to the mall. How long will it take you drive the 75 miles to the b

each?

2 answers:

Tanya [424]3 years ago

8 0

Answer:

1 hour and 52.5 minutes

Step-by-step explanation:

double the miles and minutes then half both of them

Y_Kistochka [10]3 years ago

5 0

Answer:

45/30 = 1.5 minutes per mile

75 * 1.5 = 112.5 minutes (1 hour 52.5 minutes)

Step-by-step explanation:

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What is y<-1/2x+1 and y≤x-2??

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This is your perfect answer

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3 years ago

A cellular phone company monitors monthly phone usage. The following data represent the monthly phone use in minutes of one part

Sergeu [11.5K]

Answer:

The standard deviation increased but there was no change in the interquantile range

Step-by-step explanation:

We are given the following data in the question:

320, 411, 348, 537, 420, 449, 462, 403, 454, 517, 515, 358, 438, 541, 387, 368, 502, 437, 431, 428.

n = 20

a) Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{8726}{20} = 436.3$

Sum of squares of differences =

13525.69 + 640.09 + 7796.89 + 10140.49 + 265.69 + 161.29 + 660.49 + 1108.89 + 313.29 + 6512.49 + 6193.69 + 6130.89 + 2.89 + 10962.09 + 2430.49 + 4664.89 + 4316.49 + 0.49 + 28.09 + 68.89 = 75924.2

$S.D = \sqrt{\frac{75924.2}{19}} = 63.21$

Sorted Data = 320, 348, 358, 368, 387, 403, 411, 420, 428, 431, 437, 438, 449, 454, 462, 502, 515, 517, 537, 541

$IQR = Q_3 - Q_1\\Q_3 = \text{upper median},\\Q_1 = \text{ lower median}$

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$

$Median = \frac{431 + 437}{2} = 434$

$Q_1 = \frac{387 + 403}{2} = 395\\\\Q_3 = \frac{462 + 502}{2} = 482$

IQR = $482 - 395 = 87$

b) After changing the observation

0, 411, 348, 537, 420, 449, 462, 403, 454, 517, 515, 358, 438, 541, 387, 368, 502, 437, 431, 428

$Mean =\displaystyle\frac{8406}{20} = 420.3$

Sum of squares of differences =

176652.09 + 86.49 + 5227.29 + 13618.89 + 0.09 + 823.69 + 1738.89 + 299.29 + 1135.69 + 9350.89 + 8968.09 + 3881.29 + 313.29 + 14568.49 + 1108.89 + 2735.29 + 6674.89 + 278.89 + 114.49 + 59.29 = 247636.2

$S.D = \sqrt{\frac{247636.2}{19}} = 114.16$

Sorted Data = 0, 348, 358, 368, 387, 403, 411, 420, 428, 431, 437, 438, 449, 454, 462, 502, 515, 517, 537, 541

$Median = \frac{431 + 437}{2} = 434$

$Q_1 = \frac{387 + 403}{2} = 395\\\\Q_3 = \frac{462 + 502}{2} = 482$

IQR = $482 - 395 = 87$

Thus. the standard deviation increased but there was no change in the interquantile range.

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3 years ago

What is the formed of the fact family for 6,7,13 what is the answer

Keith_Richards [23]

Answer:

7 + 6 = 13

13 = 7 + 6

13 – 6 = 7

7 = 13 – 6

Step-by-step explanation:

7 + 13 = 20

13 + 7 = 20

13 – 13 = 0

13 – 0 = 13

7 + 0 = 7

6 + 0 = 6

13 – 0 = 13

13 – 13 = 0

7 + 0 = 7

6 + 0 = 6

13 – 0 = 13

13 – 13 = 0

7 + 6 = 13

13 = 7 + 6

13 – 6 = 7

7 = 13 – 6

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2 years ago

0.12 over 0.20 as a percent

Afina-wow [57]

$\dfrac{0.12}{0.2} = \dfrac{0.12 \times 100}{0.2 \times 100} = \dfrac{12}{20}$

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3 years ago

Factor ab + bc + b2 + ac.

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3 years ago

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