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-Dominant- [34]
2 years ago
8

The best fitting line minimizes the sum of the squared errors when using ______. Multiple choice question. the high-low method s

cattergraph analysis least-square regression
Mathematics
1 answer:
ki77a [65]2 years ago
6 0

Answer:

C.) least-square regression

I hope this helps! ^-^

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Y’all I’m bored what y’all wanna do?
charle [14.2K]

Answer: eat, sleep, and watch anime

Step-by-step explanation: :)

4 0
3 years ago
Read 2 more answers
If she spends all of her income on breadfruits and melons, Natalie can just afford 9 breadfruits and 10 melons per day. She coul
pshichka [43]

Answer:

$312

Step-by-step explanation:

Now, what we need to know is the cost of a melon since we know the cost of a bread fruit to be 8 yen.

What the question is simply saying is that the cost of 9 breadfruits and 10 melon equals the cost of 3 breadfruits and 12 melons.

To get her income per day, we need to get the amount she buys each melon. Let this amount be x yen.

Mathematically: 9(8 yen) + 10(x yen) = 3(8 yen) + 12(x yen)

Opening the brackets: 72 + 10x = 24 + 12x

48 = 2x , x = 24 yen

Her total daily income is thus 9(8) + 10(24) = 72 + 240 = $312

3 0
4 years ago
What is the area of a circle with a diameter of 34 mi? Use 3.14 for n
klio [65]

Answer:

907.46

Step-by-step explanation:

diameter = 34

radius = 17 (half of diameter)

A=πr^2

HOPE THIS HELPS PLZ MARK BRAINLIEST! :)

3 0
3 years ago
A coffee table is on sale for 20% off the original price of $115.
Angelina_Jolie [31]
The answer would be $98.90
4 0
3 years ago
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What is the sum of a 12-term arithmetic sequence where the last term is 13 and the common difference is -10?
Y_Kistochka [10]
\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=12\\
d=-10\\
a_{12}=13
\end{cases}
\\\\\\
a_{12}=a_1+(12-1)d\implies 13=a_1+(12-1)(-10)
\\\\\\
13=a_1-110\implies \boxed{123=a_1}

\bf \\\\
-------------------------------\\\\
\textit{sum of a finite arithmetic sequence}\\\\
S_n=\cfrac{n}{2}(a_1+a_n)\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
a_n=\textit{value of the }n^{th}\ term\\
------------\\
n=12\\
a_1=123\\
a_{12}=13
\end{cases}
\\\\\\
S_{12}=\cfrac{12}{2}(a_1+a_{12})\implies S_{12}=\cfrac{12}{2}(123+13)

and surely you know how much that is.
6 0
4 years ago
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