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SVETLANKA909090 [29]

2 years ago

5

Solve for x. -2(-4x - 1) = x + 3 = -30

1 answer:

FinnZ [79.3K]2 years ago

4 0

Here is the equation if needed. the answer is x=-4.1429

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Please help I really don’t understand anything at all !

Lesechka [4]

Answer:

see explanation

Step-by-step explanation:

1

2(3x + 1) = 4(x + 2) ← distribute parenthesis on both sides

6x + 2 = 4x + 8 ( subtract 4x from both sides )

2x + 2 = 8 ( subtract 2 from both sides )

2x = 6 ( divide both sides by 2 )

x = 3

------------------------------------------------------------

2

6x = 4(x - 3) ← distribute parenthesis

6x = 4x - 12 ( subtract 4x from both sides )

2x = - 12 ( divide both sides by 2 )

x = - 6

-----------------------------------------------------------

3

2(4x + 7) = 4x + 30 ← distribute parenthesis on left side

8x + 14 = 4x + 30 (subtract 4x from both sides )

4x + 14 = 30 ( subtract 14 from both sides )

4x = 16 ( divide both sides by 4 )

x = 4

---------------------------------------------------------------------

4

50 = - (y + 22) ← distribute parenthesis by - 1

50 = - y - 22 ( add 22 to both sides )

72 = - y ( multiply both sides by - 1 )

- 72 = y , that is

y = - 72

7 0

2 years ago

Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a tha

const2013 [10]

Answer:

(a) The value of <em>a</em> is 53.35.

(b) The value of <em>a</em> is 38.17.

(c) The value of <em>a</em> is 26.95.

(d) The value of <em>a</em> is 25.63.

(e) The value of <em>a</em> is 12.06.

Step-by-step explanation:

The probability density function of <em>X</em> is:

$f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}$

Here, 22 < X < 55.

(a)

Compute the value of <em>a</em> as follows:

$P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35$

Thus, the value of <em>a</em> is 53.35.

(b)

Compute the value of <em>a</em> as follows:

$P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17$

Thus, the value of <em>a</em> is 38.17.

(c)

Compute the value of <em>a</em> as follows:

$P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95$

Thus, the value of <em>a</em> is 26.95.

(d)

Compute the value of <em>a</em> as follows:

$P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63$

Thus, the value of <em>a</em> is 25.63.

(e)

Compute the value of <em>a</em> as follows:

$P(1.83\leq X\leq a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06$

Thus, the value of <em>a</em> is 12.06.

7 0

3 years ago

Using the data shown on the graph, which statements are correct

Tomtit [17]

Answer:

B, C, and E

Step-by-step explanation:

Let's consider each option given the graph shown above:

A. The ratio of x/y can be found using any point on the line, say, (5, 6). Thus, ratio of x/y = 5/6, not 6/5.

Option A is not correct.

B. If you check for y/x for any given point along the line, we would have the same result. So the ratio of y/x is consistent. Option B is correct.

C. The graph has a line that runs through the point of origin, so therefore, it represents a proportional relationship.

Option C is correct

D. If option C is correct, then option D is not correct.

E. If option C is correct, then option E is correct.

8 0

2 years ago

Find the first three terms of the series represented by the formula 3(- 2)(n - 1).

enyata [817]

Answer:

0, - 6, - 12

Step-by-step explanation:

To find the first 3 terms, substitute n = 1, 2, 3 into the formula

a₁ = 3(- 2)(1 - 1) = 3 × - 2 × 0 = 0

a₂ = 3(- 2)(2 - 1) = 3 × - 2 × 1 = - 6

a₃ = 3(- 2)(3 - 1) = 3 × - 2 × 2 = - 12

First 3 terms are 0, - 6, - 12

8 0

2 years ago

Which algebraic rule describes the transformation?

Olegator [25]

Answer:

C) (x,y) -> (-x,-y)

Step-by-step explanation:

This is the answer because the graph was flipped. If you look a the x point, it is in the same number, but the number is negative, and this is the same for the y point. hope this helps

7 0

3 years ago