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GenaCL600 [577]

3 years ago

14

Antonio is making a mini waffle cones. Each waffle cone is 3 inches high and has a radius of 3/4 inches. What is the volume of t

he cone

1 answer:

castortr0y [4]3 years ago

3 0

I got 7.065 for my answer.

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How to Write the numbers 0.253 in two other forms

GrogVix [38]

Answer:

253/1000, 23.5%

Step-by-step explanation:

4 0

2 years ago

yLab and Mastering3.3.43Question HelpIn triangle ABC, the measure of angle Bis 15 more than three times the measure of angle A.

lora16 [44]

∠A = 24°

∠B = 87°

∠A = 24°

Explanation:

The sum of angles in a triangle is 180 degrees

let measure of angle A = ∠A

∠B = 15 more than three times the measure of angle A

∠B = 15 + 3∠A

∠C = 45° more than the measure of angle A

∠C = 45° + ∠A

∠A + ∠B + ∠C = 180° (sum of angles in a triangle)

∠A + 15 + 3∠A + 45° + ∠A = 180

collect like terms:

∠A + 3∠A + ∠A + 15 + 45 = 180

5∠A + 60 = 180

5∠A = 180 -60

5∠A = 120

∠A = 120/5

∠A = 24°

∠B = 15 + 3∠A = 15 + 3(24)

∠B = 87°

∠C = 45° + ∠A = 45° + 24°

∠C = 69°

8 0

1 year ago

What is the minum of two colors needed?

Alexus [3.1K]

4 colour needed for this…i think

8 0

2 years ago

The table below shows the number of invertebrates found in a tide pool. Find the ratio of crabs to the total number of invertebr

Kitty [74]

The ratio is 9:52. Meaning there is 9 crabs in the tide pool compared to all other invertebrates in the tide pool (including crabs). Crabs are also probably higher on the food chain because there is less of them, meaning they require more food then the other invertebrates.
Hope this helps!

4 0

3 years ago

Use the model below to estimate the average annual growth rate of a certain country's population for 1950, 1988, and 2010, where

Morgarella [4.7K]

Answer:

The average annual growth rate of a certain country's population for 1950, 1988, and 2010 are 2.398, 0.9985 and 0.2236 respectively.

Step-by-step explanation:

The given equation is

$Y=-0.0000084x^3+0.00211x^2-0.205x+8.423$

Where Y is the annual growth rate of a certain country's population and x is the number of years after 1900.

Difference between 1950 and 1900 is 50.

Put x=50 in the given equation.

$Y=-0.0000084(50)^3+0.00211(50)^2-0.205(50)+8.423$

$Y=2.398$

Therefore the estimated average annual growth rate of the country's population for 1950 is 2.398.

Difference between 1988 and 1900 is 88.

Put x=88 in the given equation.

$Y=-0.0000084(88)^3+0.00211(88)^2-0.205(88)+8.423$

$Y=0.9984752\approx 0.9985$

Therefore the estimated average annual growth rate of the country's population for 1988 is 0.9985.

Difference between 2010 and 1900 is 110.

Put x=110 in the given equation.

$Y=-0.0000084(110)^3+0.00211(110)^2-0.205(110)+8.423$

$Y=0.2236$

Therefore the estimated average annual growth rate of the country's population for 2010 is 0.2236.

8 0

2 years ago