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Anna71 [15]
2 years ago
11

Can someone help me

Mathematics
1 answer:
Sergio039 [100]2 years ago
3 0

Answer:

12. √197

13. √89

14. 2√10

15.  (-3, 2)

16. (3/2, 0)

17. (2, -8)

18. 21

Step-by-step explanation:

12. Point 1: (-8, -2); Point 2: (6, -1)

d = √(x2 - x1)² + (y2 - y1)²

d = √(6 - (-8)² + (-1 - (-2)²

d = √(14)² + (1)²

d = √196 + 1

d = √197

13. Point 1: (-4, 5); Point 2: (4, 0)

d = √(x2 - x1)² + (y2 - y1)²

d = √(4 - (-4))² + (0 - 5)²

d = √(8)² + (-5)²

d= √64 + 25

d = √89

14. G: (-2, -3); H: (0, 3)

d = √(x2 - x1)² + (y2 - y1)²

d = √(0 - (-2))² + (3 - (-3))²

d = √(-2)² + (6)²

d = √4 + 36

d = √40

d = √4 x 10

d = 2√10

15. Point 1: (-1, -5); Point 2: (-5, 9)

Midpoint = ((x1 + x2))/2, ((y1 + y2))/2

Mid = (-1 + (-5)/2, (-5 + 9)/2

Mid = (-6)/2, (4)/2

Mid = (-3, 2)

16. Point 1: (7, -2); Point 2: (-4, 2)

Midpoint = ((x1 + x2))/2, ((y1 + y2))/2

Mid = (7 + (-4)/2, (-2 + 2)/2

Mid = (3)/2, (0)/2

Mid = (3/2, 0)

17. M:(-3, -1); Y:(-8, 6), X: (X, y)

Midpoint = ((x1 + x2))/2, ((y1 + y2))/2

X      = ((-8 + x2))            ,((6 + y2))

                ÷      = -3              ÷           = -1

                2                          2

To get rid of the 2 multiply the 2 by -3 for X and -1 for Y

X = ((-8 + x2))                      ,((6 + y2))

             ÷       = -3(2)                 ÷         = -1(2)

           2(2)                              2(2)

X = (-8 + x2) = -6, (6 + y2) = -2

           +8          +8,   -6             -6

X2 = 2, Y2 = -8

X: (2, -8)

18. QR = 8x - 51; RS = 3x - 6

8x - 51 = 3x - 6

-3x         -3x

5x - 51 = -6

     + 51   +51

5x = 45

÷5    ÷5

x = 9

QR = 8(9) - 51

QR = 72 - 51

QR = 21

RS = 3x - 6

RS = 3(9) - 6

RS = 21

(QR + RS)/2

(21 + 21)/2

42/2 = 21

QS = 21

I really hope this helps!

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<span>Calculate 9 x 8, which is 72.
Since 72 is two-digit, we carry the first digit 7 to the next column.
</span>
3 <span>Calculate 8 x 8, which is 64. Now add the carry digit of 7, which is 71.
Since 71 is two-digit, we carry the first digit 7 to the next column.
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