1. Know what you're looking for:
The range is the difference between the lowest and highest values.
Your weight is 145.2 and can vary from the actual weight by maximum 0.3 lbs less or maximum 0.3 lbs more.
2. Calculate your lowest and highest values :
Lowest : 145.2 - 0.3 = 144.9 lbs
Highest : 145.2 + 0.3 = 145.5 lbs
3. Calculate the range of actual weights of the object :
145.5 - 144.9 = 0.6 lbs
--> The answer is: <u>The range of actual weights of the object is 0.6 lbs.</u>
There you go! I really hope this helped, if there's anything just let me know! :)
Answer:
$1500
6% interest
use the formula...
P(1+(r/100))^n
where P=initial amount
r=interest rate
t=time period elapsed
so ... for 5 years we get
$1500(1+(6/100))^5 = $1500(1.06)^5 = 2007.3383664
for 10 years
1500(1.06)^10 = 2686.271544814228043264
468 months = 39 years
1500(1.06)^39=14555.261231781943250017719606544
Step-by-step explanation:
3^(-3) * 10^(-2)
= 1/27 * 1/100
= 1/2700.
Answer:
Step-by-step explanation:
Given is a table showing the weights, in hundreds of pounds, for six selected cars. Also shown is the corresponding fuel efficiency, in miles per gallon (mpg), for the car in city driving.
Weight Fuel eff. x^2 xy y^2
X Y
28 20 784 560 400
3 22 9 66 484
35 19 1225 665 361
32 22 1024 704 484
30 23 900 690 529
29 21 841 609 441
Mean 26.16666667 21.16666667 797.1666667 549 449.8333333
Variance 112.4722222 1.805555556
Covariance -553.8611111
r -0.341120235
Correlaton coefficient =cov (xy)/S_x S_y
Covariance (x,y) = E(xy)-E(x)E(y)
The correlation coefficient between the weight of a car and the fuel efficiency is -0.341
I think the answer is around 1.4 as you need to multiply the area by 1/9 after finding the real area.
