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3 years ago

Use compatible numbers to estimate the quotient

Mathematics

1 answer:

maksim [4K]3 years ago

7 0

Answer:

you would have to round your answers to the nearest whole number

Step-by-step explanation:

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Cual es el área del cuadrado? Ayuda porfi

Nadya [2.5K]

Include two types of translations so that we may help you better

7 0

3 years ago

A chef plans to mix 100% vinegar with Italian dressing. The Italian dressing contains 12%

Hitman42 [59]

Answer:

Amount of vinegar. 100% : 20 milliliters

Amount of Italian dressing: 140 milliliters

Step-by-step explanation:

Let's call A the amount of vinegar. 100%

Let's call B the amount of Italian dressing . 12% vinegar

The resulting mixture should have 23% vinegar, and 160 milliliters.

Then we know that the total amount of mixture will be:

$A + B = 160$

Then the total amount of pure antifreeze in the mixture will be:

$A + 0.12B = 0.23 * 160$

$A + 0.12B = 36.8$

Then we have two equations and two unknowns so we solve the system of equations. Multiply the first equation by -1 and add it to the second equation:

$-A -B = -160$

$A + 0.12B = 36.8$

--------------------------------------

$-0.88B = -123.2$

$B = \frac{-123.2}{-0.88}$

$B = 140\ milliliters$

We substitute the value of B into one of the two equations and solve for A.

$A + 140 = 160$

$A = 20\ milliliters$

7 0

3 years ago

Lori can do 42 push-ups. This is ten less than twice the amount of push-ups her sister can do. How many push-ups can her sister

densk [106]

Her sister can do 16 push ups

5 0

3 years ago

Read 2 more answers

Divide x to the 1 half power divided by x to the 2 sevenths power.

juin [17]

$\frac{x^\frac{1}{2} }{x^\frac{2}{7}}$

According to the rule of exponents $\frac{a^m}{a^n} = a^{(m-n)}$ , i.e. when two terms are in division with same base , we subtract the exponents

$\frac{x^\frac{1}{2} }{x^\frac{2}{7}} = x^{(\frac{1}{2}) - (\frac{2}{7})}$

$=x^\frac{3}{14}$

x to the 3 fourteenths power

5 0

3 years ago

A tank contains 100 gal of brine made by dissolving 80 Ib of salt in water. Pure water runs into the tank at the rate of 4 gal/m

ohaa [14]

Answer:

Step-by-step explanation:

Amount of brine = 100 gal

amount of salt = 80 lb

rate of water running = 4 gal / min

Let A be the amount of salt in lb in the tank at any time t.

(a) dA/dt = rate of salt in - rate of salt out

Rate of salt in = 0

rate of salt out = A x 4 / 100 = A / 25 lb/min

So, dA/dt = 0 - A/25 = - A/25 lb/min

$\frac{dA}{A}=-\frac{1}{25}dt$

$\int \frac{dA}{A}=-\frac{1}{25}\int dt$

$A(t) = C e^{-0.04t}$

When t = 0, A = 80 lb

So,

$A(t) = 80 e^{-0.04t}$

(b) Now, A = 40 lb

So,

$40 = 80 e^{-0.04t}$

$0.5 = e^{-0.04t}$

take log on both the sides

$ln 0.5 = - 0.04 t$

t = 17.3 minutes

8 0

3 years ago