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2 years ago

7

The table below helps to change centimetres into inches.

1 answer:

Aloiza [94]2 years ago

7 0

Answer:

5.51181 Inches

Step-by-step explanation:

No table is provided, to turn cm to inches divide the cm by 2.54, if you need help with division contact me, thank you.

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Solve the system of equations by using substitution.<br> x+8y=-2<br> x-3y=20

zysi [14]

Answer:

(14, -2)

Step-by-step explanation:

To solve by using substitution, begin by solving for a variable in the first equation. Let's solve for x:

$x+8y=-2\\x=-2-8y$

Now we know what <em>x</em> equals. Let's substitute this into the second equation:

$x-3y=20\\(-2-8y)-3y=20$

We can then simplify:

$-2-8y-3y=20$ Given equation

$-2-11y=20$ Combine y terms

$-11y=22$ Add 2

$y=-2$ Divide by -11

So, we now know the value of y = -2.

To find the value of X, we can substitute the value of Y into one of the equations. Let's use the first one:

$x+8y=-2$

$x+8(-2)=-2$ Substitute for y

$x-16=-2$ Distribute 8

$x=14$ Add 16

So, we now know the value of x = 14.

Therefore, we know a solution to the system of equations is (14, -2).

4 0

3 years ago

Which number line shows the solution set for 1-3 352

Andrej [43]

-4

Step-by-step explanation:

-4 show the number of wveryshaoaknd

8 0

3 years ago

If f(x) = 2x 2 + 3, find f(3).<br> 31<br> 15<br> 21<br> 39

Westkost [7]

21 is the right answer goodluck

7 0

3 years ago

Read 2 more answers

Use the exponential decay model, Upper A equals Upper A 0 e Superscript kt, to solve the following. The half-life of a certai

Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

$A=A_0 e^{kt}$

Where,

$A_0$ = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = $\frac{A_0}{2}$ ,

i.e.

$\frac{A_0}{2}=A_0 e^{19k}$

$\frac{1}{2} = e^{19k}$

$0.5 = e^{19k}$

Taking ln both sides,

$\ln(0.5) = \ln(e^{19k})$

$\ln(0.5) = 19k$

$\implies k = \frac{\ln(0.5)}{19}\approx -0.03648$

Now, if the substance to decay to 78% of its original amount,

Then $A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0$

$0.78 A_0=A_0 e^{-0.03648t}$

$0.78 = e^{-0.03648t}$

Again taking ln both sides,

$\ln(0.78) = -0.03648t$

$-0.24846=-0.03648t$

$\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7$

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0

3 years ago

15. Sonny has $75 to spend. The purchase he wants to make requires $93.

Rina8888 [55]

Answer:

Hello!!

If Sonny has $75 to spend and the purchase he would like to make requires $93. If he borrows extra money, he would need to borrow <u>$18</u> dollars.

Step-by-step explanation:

$93-75=18$

Hope this helps!!

4 0

3 years ago