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2 years ago

An airplane cruises 1 kilometer in 1/12 of a minute. What is its cruising speed?

Mathematics

1 answer:

VashaNatasha [74]2 years ago

6 0

Answer:

the plain is going 12km in one minute

Step-by-step explanation:

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Question:

12345 [234]

Answer:

A. Area in square inches = 1760 square inches

B. Area in square feet = 12.2 square feet

C. 1 square inch = $\frac{1}{144}$ feet

Step-by-step explanation:

Given,

Length of the rectangle (l) = 55 inches

Breath of the rectangle (b) = 32 inches

A. Area of the rectangle = length × breath

⇒ 55 × 32

⇒ 1760 square inches

Area in square inches = 1760 square inches

B. 1 foot = 12 inches

1 inch = $\frac{1}{12}$ feet

1 square inch = $\frac{1}{144}$ feet

∴ 1760 square inches = $\frac{1760}{144}$ feet

⇒ 12.2222 square feet

Area in square feet = 12.2 square feet

C. 1 square inch = $\frac{1}{144}$ feet

8 0

3 years ago

What percentage of the original price is the sale price

marta [7]

Answer:

65%

Step-by-step explanation:

this is because there is need for us to multiply 65% by $58.00

5 0

3 years ago

A rectangular swimming pool has an area of (70x+10) square feet. Find possible dimensions of the pool.

NNADVOKAT [17]

Answer:

10 and 7x + 1

Step-by-step explanation:

The area of a rectangle is 70x + 10.

Let's factor 70x + 10.

Factor out a common factor of 10.

70x + 10 = 10(7x + 1)

Since the area of a rectangle is length * width, we can let one factor be the length and the other factor be the width.

Possible dimensions are 10 and 7x + 1

6 0

3 years ago

Read 2 more answers

Solve x^2+ 4x =15<br> thxssss

dmitriy555 [2]

Answer:

x=3/5

Step-by-step explanation:

x^2+4x=5

x+4x=5x

5x+2=5

-2 -2

5x=3

divide 5 from each side

5/5x=3/5

7 0

3 years ago

Given sin theta= 6/11 and sec theta < 0, find cos theta and tan theta.

bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

$cos^2(\theta)=1-sen^2(\theta)\\\\tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

Substitute $sin(\theta)=\frac{6}{11}$ into the first equation, solve for the cosine and simplify. Then, you obtain:

$cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}$

As $sec\theta$ then $cos\theta$ :

$cos(\theta)=-\frac{\sqrt{85}}{11}$

Now we can find $tan\theta$ :

$tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}$

4 0

3 years ago

Read 2 more answers