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Sergeu [11.5K]
3 years ago
14

Got It? Do these problemst

Mathematics
1 answer:
dedylja [7]3 years ago
6 0
I did where you subtract 4 from both sides then divide 2 from 4 and you get 0.5 as x for your answer but im not sure
You might be interested in
Solving Exponential and Logarithmic Equation In exercise,solve for x or t.See example 5 and 6.
Virty [35]

Answer:

x=\frac{6e^3}{e^3-1}

Step-by-step explanation:

ln x - ln(x - 6) = 3

Apply natural log property

ln mn=ln m + ln(n), ln(m/n)=ln(m)-ln(n)

ln x - ln(x - 6) = 3

ln(\frac{x}{x-6} )=3

All natural log has base 'e'

\frac{x}{x-6} =e^3

cross multiply

x=e^3(x-6)

x=e^3x-6e^3

add 6e^3 on both sides and -x on both sides

6e^3=e^3x-x

6e^3=x(e^3-1)

Divide e^3-1 on both sides

x=\frac{6e^3}{e^3-1}

5 0
4 years ago
What is 11/12 of a full rotation
loris [4]

Answer:

Turn-0.9166666666666666

Degree-330.00000000081860208

8 0
3 years ago
You have a $9000 bond that earns 3% interest compounded quarterly. How much is the bond word at 6 years?
Vlad1618 [11]

Answer:

$10,667.66

Step-by-step explanation:

The formula for calculating the compound interest is expressed as:

A = P(1+r/n)^nt

P is the principal = $9000

r is the rate = 3%

time t = 6years

n = 1/4

Substitute

A = 9000(1+0.03/(1/4))^6/4

A = 9000(1+0.03(4))^1.5

A = 9000(1+0.12)^1.5

A = 9000(1.12)^1.5

A = 9000(1.1853)

A = 10,667.67

Hence the amount after 6 years is $10,667.66

5 0
3 years ago
ABDC is an isosceles trapezoid. Given only the choices below, which properties would you use to prove ACD ≅ BDC by SSS?
Alexeev081 [22]
I think the correct answer would be the first option. To prove that ACD ≅ BDC by virtue of the SSS or side-side-side postulate, it should be that the answer is related with the sides of the trapezoid and the best option would be that the <span> legs are congruent.</span>
4 0
3 years ago
Read 2 more answers
Lee's summer job was to sell newspapers. He sold 24 in the morning. In the afternoon, he sold 2/7 of the remaining newspapers. T
Nikolay [14]
Given:
x = beginning number of newspapers
24 = sold in the morning
(x - 24) * 2/7 = sold in the afternoon
x * 1/2 = remaining newspapers

5/7 of the remaining newspaper is equal to 1/2 of the original number.

(x - 24) * 5/7 = 1/2 * x 
5x/7 - 120/7 = x/2
5x/7 * 2/2 - 120/7 * 2/2 = x/2 * 7/7
10x/14 - 240/14 = 7x/14
10x/14 - 7x/14 = 240/14
3x/14 = 240/14
14 * 3x/14 = 14 * 240/14
3x = 240
x = 240/3
x = 80

80 - 24 = 56 remaining newspaper in the morning
56 * 2/7 = 16 sold in the afternoon
80 - 24 - 16 = 80/2
40 = 40 remaining newspaper for the day.
5 0
3 years ago
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