If the arc measures 250 degrees then the range of the central angle lies from π to 1.39π.
Given that the arc of a circle measures 250 degrees.
We are required to find the range of the central angle.
Range of a variable exhibits the lower value and highest value in which the value of particular variable exists. It can be find of a function.
We have 250 degrees which belongs to the third quadrant.
If 2π=360
x=250
x=250*2π/360
=1.39 π radians
Then the radian measure of the central angle is 1.39π radians.
Hence if the arc measures 250 degrees then the range of the central angle lies from π to 1.39π.
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Answer: it will take 14 years
Step-by-step explanation:
A savings account is started with an initial deposit of $600. This means that the principal P is
P = 600
It was compounded annually. This means that it was compounded once in a year. Therefore,
n = 1
The rate at which the principal was compounded is 2.1%. So
r = 2.1/100 = 0.021
The duration of time that for which the money stayed in the account is t years. So
Time = t
The formula for compound interest is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years. Therefore,
a) the equation to represent the amount of money in the account as a function of time in years would be
A = 600 (1+0.021/1)^1×t
A = 600 (1.021)^t
b) the amount of time it takes for the account balance to reach $800 would be
800 = 600 (1.021)^t
Dividing both sides of the equation by 600, it becomes
1.33 = (1.021)^t
t = 14
SNKRS watch Poseidon last by laughably Lance
You can show that 
by constructing a triangle.
Take two points, O(0, 0) and A(1, 0), and let B be the point on the unit circle such that the angle between the line segments OA and OB is 
radians.
Since both A and B lie on the circle, the line segments OA and OB both have length 1 (same as the circle's radius). We finish constructing the triangle by connect A and B.
Since OB and OA have the same length, triangle OAB is isosceles, but more than that, it's also equilateral. Why? Because the interior angles of any triangle always add to 
radians. We know one of the angles is radians, which leaves a contribution of 
radians between the remaining angles A and B. Angles A and B must be congruent (because OAB is isosceles), which means they also have measure radians.
Next, draw an altitude of the triangle through point B, and label the point where it meets the "base" OA, C. Since OAB is equilateral, the altitude BC is also a perpendicular bisector. That means OC has length 
, and by definition of 
we have
The answer is 12.48 hope this helps!
