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Blababa [14]
3 years ago
12

It is 8 a.m. and the animals are waking up. In exactly 5 minutes. Sarah will chirp. Sarah will then chirp every 5 minutes until

10 a.m.! To make matters worse, in exactly 13 minutes, Alex will chirp. Alex will then chirp every 13 minutes until 10 a.m.! How many times will both of them be making noise at exactly the same time? Explain how you solved it
Mathematics
2 answers:
VMariaS [17]3 years ago
8 0

Answer:

Once.

Step-by-step explanation:

To find when they chirp together, we must find the LCM of the two numbers. The LCM, or least common multiple of 13 and 5 is 65. Therefore, after 65 minutes is the first time they chirp together. Then we can multiply 65 by 2 to see if they chirp a second time. 65x2 is 130, but 8AM-10AM is only 120 minutes, therefore they do not chirp together more than 1 time.

artcher [175]3 years ago
7 0

what the top guy said was right

hoped that helped:P

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eduard

Answer:

a. 2^(x-2) = g^(-1)(x)

b. A, B, D

Step-by-step explanation:

the phrasing attached in the image is flagged as inappropriate, so i will be replacing it with g(x) and its inverse with g^(-1)(x)

1. replace g(x) with y and solve for x

y = log₂(x) + 2

subtract 2 from both sides to isolate the x and its log

y - 2 = log₂(x)

this text is replaced by the second image -- it was marked as inappropriate

thus, 2^(y-2) = x

replace x with g^(-1)(x) and y with x

2^(x-2) = g^(-1)(x)

2. plug this in to points A, B, C, D, E, and F

A: (2,1)

plug 2 in for x

2^(2-2) = 2⁰ = 1 so this works

B: (4, 4)

2^(4-2) = 2²= 4 so this works

C: (9, 3)

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(5, 8)

2^(5-2) = 2³ = 8 so this works

E: (3, 5)

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F: (8, 5)

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