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Andrej [43]
3 years ago
9

Given f(x)=-4x-2 solve for x when f(x)=6

Mathematics
1 answer:
Paladinen [302]3 years ago
4 0

Answer:

-26

Step-by-step explanation:

1. Replace the x with 6

2. Multiply -4 by 6 to get -24

3. Subtract 2 from -24 to get -26

-26 is the answer.

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After saving 53% of his allowance, spending 26% of his allowance on food, and using $2 of the $20 allowance to pay library fines
Flura [38]
His allowance is $20
He saves 20(.53)
He spends 20(.26)
He uses $2

20 - 20(.53) - 20(.26) - 2 = Money left
6 0
3 years ago
Read 2 more answers
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
defon

Answer:  84

<u>Step-by-step explanation:</u>

Set up a proportion as follows: \dfrac{\text{students that practice everyday}}{\text{total students}}

\dfrac{7}{12}=\dfrac{x}{144}

Cross multiply: 12x = 7 × 144

Divide by 12:         x = 7 × 12

Simplify:                x = 84

6 0
3 years ago
Write the equation of the line with a slope of 1/2
Arada [10]

Answer:

y = (-1/2)x - 1

Step-by-step explanation:

y - 1 = (-1/2)(x - (-4))

y - 1 = (-1/2)(x + 4)

y - 1 = (-1/2)x -(1/2)(4)

y - 1 = (-1/2)x - 2

y = (-1/2)x -2 + 1

3 0
3 years ago
Anthony's bedroom and bathroom are both rectangular and have a combined area of 240 square feet. His bathroom has a length of 6
ivolga24 [154]

Answer:

Step-by-step explanation:

240 | Total

6x10=60 square feet | Bathroom

240-60=180

Square foot of 180 is 16.7225

Length of Anthony's bathroom is 16.7225

5 0
3 years ago
The width of a circular track is 2 meters. If the radius of the outer circle is 6 meters, find the area of the track.​
Vilka [71]

Answer:

62.8 \:  {m}^{2}

Step-by-step explanation:

Radius of outer circle = 6 m

Width of the track = 2 m

So, radius of inner circle = 6 - 2 = 4 m

Area of the track = Area of outer circle - Area of inner circle

= \pi {6}^{2}  - \pi {4}^{2}  \\  \\  = \pi( {6}^{2}  -  {4}^{2} ) \\  \\  = 3.14 \times (36 - 16) \\  \\  = 3.14 \times 20 \\  \\  = 62.8 \:  {m}^{2}

4 0
3 years ago
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