Question

The width of a circular track is 2 meters. If the radius of the outer circle is 6 meters, find the area of the track.​

Answer 1

Answer:

$62.8 \: {m}^{2}$

Step-by-step explanation:

Radius of outer circle = 6 m

Width of the track = 2 m

So, radius of inner circle = 6 - 2 = 4 m

Area of the track = Area of outer circle - Area of inner circle

$= \pi {6}^{2} - \pi {4}^{2} \\ \\ = \pi( {6}^{2} - {4}^{2} ) \\ \\ = 3.14 \times (36 - 16) \\ \\ = 3.14 \times 20 \\ \\ = 62.8 \: {m}^{2}$