Answer:
see below for the graph
Step-by-step explanation:
The desired graph has two y-intercepts and one x-intercept. It is not the graph of a function.
Here's one way to get there.
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Start with the parent function y = |x| and scale it down so that it has a y-intercept of -1 and x-intercepts at ±1.
Now, it is ...
f(x) = |x| -1
We want to scale this vertically by a factor of -5. this puts the y-intercept at +5 and leaves the x-intercepts at ±1.
Horizontally, we want to scale the function by an expansion factor of 3. The transformed function g(x) will be ...
g(x) = -5f(x/3) = -5(|x/3| -1) = -5/3|x| +5
This function has two x-intercepts at ±3 and one y-intercept at y=5. By swapping the x- and y-variables, we can get an equation for the graph you want:
x = -(5/3)|y| +5
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<em>Comment on this answer</em>
Since there are no requirements on the graph other than it have the listed intercepts, you can draw it free-hand through the intercept points. It need not be describable by an equation.
Answer:
<h3>16</h3>
Step-by-step explanation:
Given the equation y = 8x
From the table, we are to find the value of y when x = 2
when x = 2;
y = 8(2)
y = 8 * 2
y = 16
Hence the value that completes the table is 16
9 (3t + 4b) Distribute
9 * 3t + 9 * 4b Multiply
27t + 36b
Hope this helps!!!
Answer:Using the slope-intercept form, the y-intercept is 1