How can I solve this polynomial (x^4+4x^3-x-4)/(x^3-1)

pam cuts 75 inches of ribbon into 6 equally sized pieces with no ribbon left over whats the length in inches of each piece of ri

Elden [556K]

Answer:

12.5 inches? I think

Step-by-step explanation:

gotta go do my work

5 0

3 years ago

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What is the answer to 5m + 30 = 60

Keith_Richards [23]

Answer:

m = 6

Step-by-step explanation:

Given

5m + 30 = 60 ( subtract 30 from both sides )

5m = 30 ( divide both sides by 5 )

m = 6

6 0

3 years ago

Function h models an object's height in feet after x seconds have passed. Which equation shows that the object's height increase

ASHA 777 [7]

Answer:

C

Step-by-step explanation:

We know that function h represents an object's height in feet after x seconds.

In that case, option A) h(15) = 100 means that after 15 seconds, the object's height is 100 feet.

Option B) h(100) = 15 means that after 100 seconds, the object's height is 15 meters.

Therefore, neither A nor B are correct.

Option C) h(15) - h(0) = 100 means that between the zeroth and 15th second, their difference is 100 feet.

In other words, the object's height increased by 100 feet over the first 15-second period.

Option C is correct.

For Option D), it gives us the average rate of change. (h(15) - h(0)) / (15) = 100 means that for the first fifteen seconds, the height of the object increased at an average rate of 100 feet per second.

8 0

3 years ago

Whenever 2 line or intersect at 90 the 2 lines are said to be ?

Sedaia [141]

Two lines that intersect at 90 degrees are considered perpendicular to each other.

7 0

3 years ago

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Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118. If a recent test-taker

LuckyWell [14K]

Answer:

Probability that the student scored between 455 and 573 on the exam is 0.38292.

Step-by-step explanation:

We are given that Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118.

Let X = Math scores on the SAT exam

So, X ~ Normal( $\mu=514,\sigma^{2} =118^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean score = 514

$\sigma$ = standard deviation = 118

Now, the probability that the student scored between 455 and 573 on the exam is given by = P(455 < X < 573)

P(455 < X < 573) = P(X < 573) - P(X $\leq$ 455)

P(X < 573) = P( $\frac{X-\mu}{\sigma}$ < $\frac{573-514}{118}$ ) = P(Z < 0.50) = 0.69146

P(X $\leq$ 2.9) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{455-514}{118}$ ) = P(Z $\leq$ -0.50) = 1 - P(Z < 0.50)

= 1 - 0.69146 = 0.30854

The above probability is calculated by looking at the value of x = 0.50 in the z table which has an area of 0.69146.

Therefore, P(455 < X < 573) = 0.69146 - 0.30854 = 0.38292

Hence, probability that the student scored between 455 and 573 on the exam is 0.38292.

7 0

3 years ago