All categories

2 years ago

A store offers discounts on lunch-size chip bags when buying larger quantities. The graph below represents the total cos

Mathematics

1 answer:

Ivenika [448]2 years ago

6 0

The difference in the price per bag for 150 bags versus 50 bags is $0.05 per bag

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

From the diagram:

Price for 150 bag = $38

Cost per bag = $40 / 150 = $0.25

Also:

Price for 50 bag = $15

Cost per bag = $15 / 50 = $0.30

Difference in price = $0.30 - $0.25 = $0.05

The difference in the price per bag for 150 bags versus 50 bags is $0.05 per bag

Find out more on equation at: brainly.com/question/2972832

You might be interested in

Help please due today

Deffense [45]

The answer is 2 I believe

5 0

3 years ago

First one to answer receives 100 points and brainiest!

larisa [96]

Answer and Step-by-step explanation:

<em>116 b.</em>

$2^{10} = 1024\\2^8 = 256\\\\1024 + 256 = 1280\\\\\\2^5 = 32\\2^3 = 8\\\\32 - 8 = 24$

1280 × 24 = 30720

<u>30720 ÷ 60 = 512. 512 is the solution; the expression is divisible by 60.</u>

<em>116 c.</em>

$16^3 = 4096\\8^3 = 512\\\\4096 - 512 = 3584\\\\\\4^3 = 64\\2^3 = 8\\\\64 + 8 = 72$

3584 × 72 = 258048

<u>258048 ÷ 60 = 4096. 4096 is the solution; the expression is divisible by 63.</u>

<em>116 d.</em>

$125^2 = 15625\\25^2 = 625\\\\15625 + 625 = 16250\\\\\\5^2 = 25\\\\25 - 1 = 24$

16250 × 24 = 390000

<u>390,000 ÷ 39 = 10,000. 10,000 is the solution; the expression is divisible by 39.</u>

<u></u>

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

4 0

3 years ago

Pre-Calc: Find all the zeros of the function.

uysha [10]

The zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i and the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

<h3>What are polynomial expressions?</h3>

Polynomial expressions are mathematical statements that are represented by variables, coefficients and operators

<h3>How to determine the zeros of the polynomial?</h3>

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Set the equation to 0

So, we have

(5y - 4)(5y + 4)(25y^2 + 16) = 0

Expand the equation

So, we have

5y - 4 = 0, 5y + 4 = 0 and 25y^2 + 16 = 0

This gives

5y = 4, 5y = -4 and 25y^2 = -16

Solve the factors of the equation

So, we have

y = 4/5, y = -4/5 and y = ±4/5√i

Hence, the zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i

How to write the polynomial as a product of the linear factors?

In (a), we have

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Hence, the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)