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2 years ago

Solve for X. Round to the nearest tenth of a degree, if necessary. Show me how you solved it

Mathematics

1 answer:

Morgarella [4.7K]2 years ago

5 0

Answer:

11. 39.0°

12. 31.0°

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relations between trig functions and the angles and sides in a right triangle.

The hypotenuse and the side opposite the unknown angle are given. The relevant trig relation is ...

Sin = Opposite/Hypotenuse

sin(x°) = 39/62

The angle is found using the inverse sine function.

x° = arcsin(39/62) ≈ 39.0°

The hypotenuse and the side adjacent to the unknown angle are given. The relevant trig relation is ...

Cos = Adjacent/Hypotenuse

cos(x°) = 84/98

The angle is found using the inverse cosine function.

x° = arccos(84/98) ≈ 31.0°

<em>Additional comments</em>

These functions are found using a calculator. As shown in the attachment, the calculator must be set to show angles in degrees (not radians or grads). (This mode setting is shown in the lower left corner of the display: DEG.)

As shown in the attachment, these inverse functions are often the "second" function of the trig function keys of the calculator.

You can read these inverse functions as ...

arcsin(Q) = sin⁻¹(Q) ≡ "the angle whose sine is Q"

arccos(Q) = cos⁻¹(Q) ≡ "the angle whose cosine is Q"

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Samantha ran on a fitness track for 20 min, and then walked for 15 min. Her running rate was 230 ft per minute faster than her

Mnenie [13.5K]

Answer:

560 ft/min

Step-by-step explanation:

Let r represent Samantha's running rate in feet per minute. Then r-230 is her walking rate. We can use the relation ...

distance = speed × time

to write an equation for the total distance Samantha went.

20r + 15(r -230) = 16150

35r - 3450 = 16150 . . . . eliminate parentheses, collect terms

35r = 19600 . . . . . . . . . . add 3450

r = 560 . . . . . . . . . . . . . . divide by the coefficient of r

Samantha ran 560 feet per minute.

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3 years ago

F(x) = x^3 + 3x^2<br><br> What would the graph look like?

lapo4ka [179]

Answer: the answer is in the attachment.

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3 years ago

Read 2 more answers

Mason walked on Monday, Wensday, and Friday. Use these clues to find how far he walked each day. These distances were six-eights

krok68 [10]

Answer:

Monday he walked $\frac{1}{4}miles$

Wednesday he walked $\frac{6}{8}miles$

Friday he walked $\frac{1}{6}miles$

Step-by-step explanation:

Given Mason walked on Monday, Wednesday and Friday. These distances were six-eights mile, one-fourth mile, and one-sixth mile. He did not walk the farthest on Monday. He walked less on Friday than Monday. we have to find how far he walked each day.

distances are $\frac{6}{8}, \frac{1}{4}, \frac{1}{6}$ that are 0.75, 0.25 and 0.17 respectively.