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pantera1 [17]
3 years ago
9

*I NEED THIS ASAP*

Mathematics
1 answer:
BigorU [14]3 years ago
5 0

Answer:

5 terms

to the fourth degree

leading coeff of 1

3 turning points

end behavior (when x -> inf, y -> inf. When x -> - inf, y -> -inf)

x intercepts are (0,-4) (0,-2) (0,1) (0,3)

Relative min: (-3.193, -25) (2.193, 25)

Relative max: (-0.5, 27.563)

Step-by-step explanation:

The terms can be counted, seperated by the + and - in the equation given.

The highest exponent is your degree.

The number before the highest term is your leading coeff, if there is no number it is 1.

The turning points are where the graph goes from falling to increasing or vice versa.

End behaviour you have to look at what why does when x goes to -inf and inf.

X int are the points at which the graph crosses the x-axis.

The relative min and max are findable if you plug in the graph on desmos or a graphing calculator.

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A.  We have two lines:  y = 2-x   and   y = 4x+3 Given two simultaneous equations that are both required to be true.. the solution is the points where the lines cross...  Which is where the two equations are equal..  Thus the solution that works for both equations is when 2-x = 4x+3 because where that is true is where the two lines will cross and that is the common point that satisfies both equations.   B.  2-x = 4x+3   x     2-x      4x+3

______________

-3     5       -9

-2     4       -5

-1     3       -1

0     2        3

1     1        7

2     0      11

3    -1      15

The table shows that none of the integers from [-3,3] work because in no case does

2-x = 4x+3   To find the solution we need to rearrange the equation to the form x=n 2-x = 4x+3 2 -x + x = 4x + x +3 2 = 5x + 3 2-3 = 5x +3-3 5x = -1 x = -1/5   The only point that satisfies both equations is where x = -1/5 Find y:   y = 2-x  = 2 - (-1/5) = 2 + 1/5 = 10/5 + 1/5 = 11/5 Verify we get the same in the other equation y = 4x + 3   =  4(-1/5) + 3 = -4/5 + 15/5 = 11/5   Thus the only actual solution, being the point where the lines cross, is the point (-1/5, 11/5)   C.  To solve graphically  2-x=4x+3 we would graph both lines...   y = 2-x  and   y = 4x+3 The point on the graph where the lines cross is the solution to the system of equations ... [It should be, as shown above, the point (-1/5, 11/5)]   To graph y = 2-x   make a table.... We have already done this in part B   x     2-x                x    4x+3 _______              ________ -1    3                   -1      -1  0    2                    0       3  1    1                    1       7   Just graph the points on a cartesian coordinate system and draw the two lines.  The solution is, as stated, the point where the two lines cross on the graph.  

Hope this helps.

Step-by-step explanation:

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