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2 years ago

A toy car traveled at a rate of 24 feet per second for 8 seconds. How far did it travel

Mathematics

1 answer:

Bogdan [553]2 years ago

4 0

Answer:

192 feet

Step-by-step explanation:

you take the 24 and you multiply that by 8 seconds, and you get 192

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How do I make an equation using 0.5 for slope and 3 for y intercept

Ann [662]

The slope-intercept form of a line is y = mx + b, where m is the slope and b is the y-intercept. Since you are given the slope (0.5) and the y-intercept (3), all you have to do is substitute these given values into the equation. Substituting them in you get: y = 0.5x + 3, which is your answer.

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3 years ago

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Solutions to this equation!!

otez555 [7]

Answer:

w=3/5 or w=-5

Step-by-step explanation:

5w^2+22w=15

5w^2+22w-15=0 (quadratic equation)

a=5, b=22, c=-15

w1,2 =(-b+-sqrt(b^2-4ac))/2a

w1,2 =(-22+-sqrt(22^2-4*5*(-15))/2*5

w1,2 =(-22+-sqrt(484+300))/10

w1,2=(-22+-sqrt(784))/10

w1,2=(-22+-28)/10

w1=(-22+28)/10, w2=(-22-28)/10

w1=6/10, w2=-50/10

w1=3/5, w2=-5

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3 years ago

What would this equal up to

Dovator [93]

Answer:

Step-by-step explanation:

$\text{Count the zeros, there are seven so }10^7$

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2 years ago

This is a 2 part question. Need help with both questions please! Use the triangle for both parts of the question. Click on the f

ollegr [7]

Answer:

Part A) Option A. QR= 3 cm

Part B) Option B. SV=6.5 cm

Step-by-step explanation:

step 1

<u>Find the length of segment QR</u>

we know that

If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem Triangle QRW and Triangle QSV are similar by AA Similarity Theorem

$\frac{QR}{QS}=\frac{QW}{QV}$

we have

$QS=9\ cm$ ---> because S is the midpoint QT (QS=TS)

$QW=2\ cm$ --->because V is the midpoint QU (QW+WV=VU)

$QV=6\ cm$ --->because V is the midpoint QU (QV=VU)

substitute the given values

$\frac{QR}{9}=\frac{2}{6}$

solve for QR

$QR=9(2)/6=3\ cm$

step 2

Find the length side SV

we know that

The <u><em>Mid-segment Theorem</em></u> states that the mid-segment connecting the midpoints of two sides of a triangle is parallel to the third side of the triangle, and the length of this mid-segment is half the length of the third side

In this problem

S is the mid-point side QT and V is the mid-point side QU

therefore

SV is parallel to TU

and

$SV=(1/2)TU$

$SV=(1/2)13=6.5\ cm$

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3 years ago

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Find the solution x-2y=-26 x-y=-2

zalisa [80]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}x-2y=-26\\x-y=-2&\text{change the signs}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}x-2y=-26\\-x+y=2\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad-y=-24\qquad\text{change the signs}\\.\qquad\qquad y=24\\\\\text{Put the value of y to the second equation:}\\\\x-24=-2\qquad\text{add 24 to both sides}\\x=22$

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2 years ago