Answer:
a) v(t) = 14-2t.
b) The particle is moving in a positive direction in the interval [0,7) and it's moving a negative direction in the interval
c) the particles changes direction at t=7.
Step-by-step explanation:
Recall that . We will assume that whenever its velocity is positive, it is moving in a positive direction and that whenever the velocity is negative, it is moving in a negative direction. We know that the particle changes direction when the velocity passes from positive to negative or viceversa, as t goes by.
To calculate the velocity (t), we will derivate s(t) with respect to t. Recall that given a functio of the form its derivative is . Thus, using the properties of derivatives we get that
.
We can see that 14-2t>0 if 14>2t which is equivalent that 7>t. So the particle moves in a positive direction whenever . On the same way, 14-2t<0 when t>7 ( and it changes direction at t=7 since it passes from positive to negative.
Answer:
-6
Step-by-step explanation:
Parallel lines have equal slope. So this question is basically asking you what is the slope of this line.
Make this equation into slope intercept form.
y= -6(x-3) -2
y= -6x +16
y=mx+b
Answer:
x<2
Step-by-step explanation:
3x +12<18
collect like terms
3x <18 -12
3x<6
divide through by 3
x<2
Answer:
c = 2.9 yards
Step-by-step explanation:
2c = 42.4 - (18.3 x 2)
2c = 42.4 - 36.6
2c = 5.8
c = 5.8 / 2
c = 2.9 yards
<em>Hope that helps! :)</em>