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Masteriza [31]
2 years ago
9

Which lines are parallel? Check all that apply. Lines b, c, d, e, f are cut by transversal a. Clockwise from top left, the angle

s formed by lines b and a are blank, 89. 5 degrees, blank, blank; by lines c and a are blank, blank, blank, 91. 5 degrees; by lines d and a are blank, blank, 89. 5 degrees, blank; by lines e and a are 88. 5 degrees, blank, blank, blank; by lines f and a are blank, blank, 90. 5 degrees, blank. B is parallel to f b is parallel to d c is parallel to e c is parallel to d d is parallel to f e is parallel to f.
Mathematics
1 answer:
miv72 [106K]2 years ago
4 0

The two parallel lines will be b and d in the given question

<h3>What are parallel lines?</h3>

From the figure, we can see that

Angles formed by lines b and a are 89. 5 degrees

Angles formed by lines c and a are 91.5 degrees

Angles formed by lines d and a are 89.5 degrees

Angles formed by lines e and a are  88.5 degrees

Angles formed by lines f and a are   90.5 degrees

Since the angle formed by line b with a and d with a are equal that is 89.5

so these two lines will never intersect each other

But other lines have varied angles then they can intersect at one point

Thus the two parallel lines will be b and d in the given question

To know more about parallel lines follow.

brainly.com/question/24607467

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A researcher plants 22 seedlings. After one month, independent of the other seedlings, each seedling has a probability of 0.08 o
Andrews [41]

Answer:

E(X₁)= 1.76

E(X₂)= 4.18

E(X₃)= 9.24

E(X₄)= 6.82

a. P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= 0.00022

b. P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= 0.000001

c. P(X₁≤2) = 0.7442

Step-by-step explanation:

Hello!

So that you can easily resolve this problem first determine your experiment and it's variables. In this case, you have 22 seedlings (n) planted and observe what happens with the after one month, each seedling independent of the others and has each leads to success for exactly one of four categories with a fixed success probability per category. This is a multinomial experiment so I'll separate them in 4 different variables with the corresponding probability of success for each one of them:

X₁: "The seedling is dead" p₁: 0.08

X₂: "The seedling exhibits slow growth" p₂: 0.19

X₃: "The seedling exhibits medium growth" p₃: 0.42

X₄: "The seedling exhibits strong growth" p₄:0.31

To calculate the expected number for each category (k) you need to use the formula:

E(XE(X_{k}) = n_{k} * p_{k}

So

E(X₁)= n*p₁ = 22*0.08 = 1.76

E(X₂)= n*p₂ = 22*0.19 = 4.18

E(X₃)= n*p₃ = 22*0.42 = 9.24

E(X₄)= n*p₄ = 22*0.31 = 6.82

Next, to calculate each probability you just use the corresponding probability of success of each category:

Formula: P(X₁, X₂,..., Xk) = \frac{n!}{X_{1}!X_{2}!...X_{k}!} * p_{1}^{X_{1}} * p_{2}^{X_{2}} *.....*p_{k}^{X_{k}}

a.

P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= \frac{22!}{3!4!6!} * 0.08^{3} * 0.19^{4} * 0.42^{6}\\ = 0.00022

b.

P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= \frac{22!}{5!5!7!} * 0.08^{5} * 0.19^{5} * 0.31^{7}\\ = 0.000001

c.

P(X₁≤2) = \frac{22!}{0!} * 0.08^{0} * (0.92)^{22} + \frac{22!}{1!} * 0.08^{1} * (0.92)^{21} + \frac{22!}{2!} * 0.08^{2} * (0.92)^{20} = 0.7442

I hope you have a SUPER day!

8 0
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I cannot see the image no matter what I do

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