Answer: 1) jet streams are like rivers of wind high above in the atmosphere. these slim strips of strong winds have a huge influence on climate as they can push air masses around and affect weather patterns-- they form a bond between hot and cold air
2) lifting along fronts: when air masses interact. lifting also occurs along frontal boundaries as air masses of different temperature and moisture content interact with each other. the lifted air cools and the water vapor condences to form clouds in advance of the surface warm front
3) when the temperature difference between the cold and warm is large, thunderstorms and even tornadoes may form. thunderstorms can form at a cold front or within air masses. at a cold front, air can be forced upard quckly. within an air mass, uneven heating can produce convection and thunderstorms
It’s impossible they form the cell using gylocolyiss
Answer:
A
Explanation:
<em>The active state of cell division covers the prophase, metaphase, anaphase, and telophase. The total number of observed cells that were undergoing cell division can, thus, be calculated by adding the number of cells in each stage of the cell division.</em>
Total number of cell in division = 20+4+2+4
= 30
Probability that a randomly chose cell will be undergoing cell division = <em>number of cells in division/total number of cells</em>
= 30/200
= 0.15 or 15%
The correct option is, therefore, A.
Answer:
allelic frequency a = 30%
allelic frequency A = 70%
Explanation:
You are studying a population of sparrows in which the phenotype is determined by a single locus. Only two alleles for this locus are known for this population, which are distinguished by the codes 'A' and 'a'. The distribution of phenotypes in the population indicates that 49% of the population is homozygous 'AA', 42% is heterozygous and 9% 'aa' homozygous. How is the allele frequency for 'A' and 'a' determined based on these observations?
According to the case, the allelic frequency for A and a will be searched with the data:
homozygotes AA = 49%
heterozygotes Aa = 42%
homozygous aa = 9%
Frequency of homozygotes 'aa'
(q 2) = 9/100 = 0.09
we can obtain the allelic frequency of a through the following formula:
a (q) = √0.09
The result will be
= 0.3
we change to percentage
= 30%
we have the following formula
p + q = 1
to find the allele frequency A, represented by p
p = 1 - 0.3
we get the following result
p = 0.7
we change to percentage
= 70%
Answer:
Cell
A virus can only multiply when it is in a cell. It cannot reproduce anywhere else.