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2 years ago

There are 7 times as many males as females on the maths course at university. What fraction of the course are female?

Mathematics

1 answer:

Alinara [238K]2 years ago

3 0

Answer:

1/8

Step-by-step explanation:

Suppose there are 7 males so there will be 1 female according to the question.

So there is 1 female out of a total of 8 students. So the answer is 1/8.

Because the female is 1 out of the 8 people.

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-5x + y = -1x<br> 10x - 2y = 2

sleet_krkn [62]

Answer: Below is the first one

Step-by-step explanation: Second one is right here x=1/5+y/5

6 0

3 years ago

If the base angles of a trapezoid are congruent, what can be said about the diagonals of the trapezoid

Schach [20]

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Answer:

the diagonals are congruent

Step-by-step explanation:

If the base angles of a trapezoid are congruent, it is an isosceles trapezoid. It will be symmetrical about its center line. Each half of the trapezoid is identical (mirror image) to the other half. The diagonals are the same length.

3 0

3 years ago

The measures of two angles in a triangle are 32o and 78o. Which of the following equations could be used to find the measure of

Korvikt [17]

Answer:

32+78+x=180

Step-by-step explanation:

All triangle angles add up to 180, so add 78 and 32 then subtract it from 180 to get x, which in another form is 32+78+x=180.

6 0

3 years ago

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Its algebra 1, help!?

Brrunno [24]

First quartile is 3
The range idk
The third quartile is idk

7 0

4 years ago

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How do I solve this?

KengaRu [80]

Answer with Step-by-step explanation:

The given differential euation is

$\frac{dy}{dx}=(y-5)(y+5)\\\\\frac{dy}{(y-5)(y+5)}=dx\\\\(\frac{A}{y-5}+\frac{B}{y+5})dy=dx\\\\\frac{1}{100}\cdot (\frac{10}{y-5}-\frac{10}{y+5})dy=dx\\\\\frac{1}{100}\cdot \int (\frac{10}{y-5}-\frac{10}{y+5})dy=\int dx\\\\10[ln(y-5)-ln(y+5)]=100x+10c\\\\ln(\frac{y-5}{y+5})=10x+c\\\\\frac{y-5}{y+5}=ke^{10x}$

where

'k' is constant of integration whose value is obtained by the given condition that y(2)=0\\

$\frac{0-5}{0+5}=ke^{20}\\\\k=\frac{-1}{e^{20}}\\\\\therefore k=-e^{-20}$

Thus the solution of the differential becomes

$\frac{y-5}{y+5}=e^{10x-20}$

5 0

3 years ago

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