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katovenus [111]
3 years ago
8

How do I solve this?

Mathematics
2 answers:
aliya0001 [1]3 years ago
7 0

Answer:

Thus the solution of the differential becomes

\frac{y-5}{y+5}=e^{10x-20}

Step-by-step explanation:

KengaRu [80]3 years ago
5 0

Answer with Step-by-step explanation:

The given differential euation is

\frac{dy}{dx}=(y-5)(y+5)\\\\\frac{dy}{(y-5)(y+5)}=dx\\\\(\frac{A}{y-5}+\frac{B}{y+5})dy=dx\\\\\frac{1}{100}\cdot (\frac{10}{y-5}-\frac{10}{y+5})dy=dx\\\\\frac{1}{100}\cdot \int (\frac{10}{y-5}-\frac{10}{y+5})dy=\int dx\\\\10[ln(y-5)-ln(y+5)]=100x+10c\\\\ln(\frac{y-5}{y+5})=10x+c\\\\\frac{y-5}{y+5}=ke^{10x}

where

'k' is constant of integration whose value is obtained by the given condition that y(2)=0\\

\frac{0-5}{0+5}=ke^{20}\\\\k=\frac{-1}{e^{20}}\\\\\therefore k=-e^{-20}

Thus the solution of the differential becomes

 \frac{y-5}{y+5}=e^{10x-20}

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a student walks 8 steps east 6 steps northeast 9 steps north west what is her displacement? include magnitude and direction
kati45 [8]

The displacement is 18.03 steps, and the direction is 47.25°

<h3>How to get the displacement?</h3>

We know that displacement is the difference between the final position and the initial position.

We assume the initial position (0, 0). Let's define the positive x-axis as the east and the positive y-axis as the north.

First, the student moves 8 steps east, so she is at:

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Then she moves 6 steps northeast, so the new position is:

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Finally, she moves 9 steps due north, so we have:

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Then the final position is:

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So the displacement is:

D = (12.24, 13.24) - (0, 0) =  (12.24, 13.24)

The magnitude of the displacement is:

|D| = \sqrt{12.24^2 + 13.24^2} = 18.03

So the magnitude is 18.03 steps.

And the direction is given by the arctangent of the quotient between the y-component and the x-component:

\theta = Arctg(13.24/12.24) = 47.25 \°

If you want to learn more about displacements:

brainly.com/question/4931057

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