Step-by-step explanation:
There are a total of 4 + 1 + 9 + 6 = 20 cookies. So the probabilities of each type for a random cookie are:
P(oatmeal raisin) = 4/20 = 1/5
P(sugar) = 1/20
P(chocolate chip) = 9/20
P(peanut butter) = 6/20 = 3/10
Answer:
no of 5 kg disks is 3, and no of 2 kg disks is (10-3) i.e. 7
Step-by-step explanation:
Let the no of 2kg disks be a.
Let no of 5 kg disks be b.
2a+5b=29
a+b=10
Using substitution, we have
2(10-b) + 5b=29
20-2b+5b=29
20+3b=29
3b=9
b=3
So no of 5 kg disks is 3, and no of 2 kg disks is (10-3) i.e. 7
<u>Answer:</u>
The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744
<u>Solution:</u>
Total number of coils = number of good coils + defective coils = 88 + 12 = 100
p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) p(getting 2 good coils for second selection)
p(first selection) = p(second selection) =
Hence, p(getting 2 good coil for two selection) =
Point M bisects Line RS. The length of RS is also 44 because RM and MS are congruent and MS has a length of 22.