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trapecia [35]
3 years ago
11

There is a triangle with the height of 2 and a base of (x 1) what is the area

Mathematics
1 answer:
Marysya12 [62]3 years ago
5 0
I hope this helps you



Area=height.base/2



Area =2. (x+1)/2


Area =x+1
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seraphim [82]

Answer: A false statement implies a true statement, so the conditional statement is true

Step-by-step explanation:

4 0
3 years ago
Please help me answer it
Neko [114]
So for number 3, so for every 15 he earns, he saves 6 so
15:6=5:2

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then

write a real life proportion
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3 0
3 years ago
Please help<br> 4(x+8)+2=1/2(8x+60)
user100 [1]

Answer:

This is a contradiction

7 0
2 years ago
Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the
Rama09 [41]

<em><u>Question:</u></em>

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s   2s   3s   4s

<em><u>Answer:</u></em>

It takes 2 seconds for object to hit the ground

<em><u>Solution:</u></em>

<em><u>The given equation is:</u></em>

h(t) = -16t^2 + v_0t+h_0

Initial velocity = 27 feet/sec

h_0 = 10\ feet

Therefore,

h(t) = -16t^2 +27t+10

At the point the object hits the ground, h(t) = 0

-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0

Solve by quadratic formula,

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

7 0
3 years ago
Choose the two expressions that are equivalent to 6.5 ÷ 1.3.
kenny6666 [7]

Answer:

A & C

Step-by-step explanation:

To find the two expressions that are equivalent to 6.5 ÷ 1.3, you need to solve all of them until you get the two expressions that have a quotient of 5.

Let's begin solving!

65 ÷ 13  = 5

So now we know that A is one of our answers

65 ÷ 130 = 0.5

Not one of our answers because the quotient is not 5

650 ÷ 130 = 5

This is our other answer! We don't need to solve D because we only needed to find two expressions which are A and C.

Hope this helps you :)

8 0
2 years ago
Read 2 more answers
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