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2 years ago

Find the equation of the line passing through the points (5,21) and (-5,-29)

Mathematics

1 answer:

Assoli18 [71]2 years ago

3 0

Answer:

Look below

Step-by-step explanation:

lets have -29 be y2 and -5 be x2

21 - (-)29

5 - (-)5

Subtracting a negative is just adding it so

21 + 29 50
5 + 5 10

50/10

this simplified, is 5/1 or 5

y=5x+b

now we need to find b, so we substitute y and y

x = 5

y = 21

21=5*5=b

5*5 is 25

now we need to get to 21

25 -4 is 21

b = -4

y=5x-4

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What is the diameter of a sphere with a volume of 498 in3, to the nearest tenth of an inch

Romashka-Z-Leto [24]

Answer:

9.8 inches

Step-by-step explanation:

<h3>Formula for volume of the sphere is = 4/3πr³</h3><h3>Form and solve the equation for the radius</h3><h3>So: 4/3πr³= 498in³</h3><h3>πr³= 498in³*3/4 which = to 373.5in³</h3><h3>r³= 373.5in³/π</h3><h3>r=∛(373.5in³/π)</h3><h3>calculate r and times the result by 2 for diameter</h3><h3>it will be 9.834...</h3><h3>nearest tenth of an inch means the accuracy is 1 decimal place because nearest tenth= 1/10 or 0.1</h3><h3>So the final answer is 9.8in</h3>

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3 years ago

What is the slope of a line that is parallel to the line y=-1/5?

Hitman42 [59]

Answer:

slope = 0

Step-by-step explanation:

y = - $\frac{1}{5}$ is the equation of a horizontal line parallel to the x- axis.

Since it is parallel to the x- axis the slope = 0

Thus any line parallel to it will have a slope = 0

4 0

3 years ago

Solve.

Ksenya-84 [330]

<span>Solve.

x² + 4x + 4 = 18

A x=−4±3√ 2

B x=2±3√ 2

C x=4±9√ 2

D x=−2±3√2

</span> $x^2 + 4x + 4 = 18 \\ \\ x^2+4x+4-18= 0 \\ \\ x^2+4x-14=0 \\ \\ x_1_y_2= \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} \qquad a= 1\qquad b= 4\qquad c= -14 \\ \\ \\ x_1_y_2= \dfrac{-4\pm \sqrt{4^2-4(1)(-14)} }{2(1)} \\ \\ \\ x_1_y_2= \dfrac{-4\pm \sqrt{16-(-56)} }{2} \\ \\ \\ x_1_y_2= \dfrac{-4\pm \sqrt{72} }{2} \\ \\ \\ x_1= \dfrac{-4+ \sqrt{72} }{2} \qquad\qquad x_2= \dfrac{-4+ \sqrt{72} }{2}\\ \\ \\ x_1= \dfrac{-4+ \sqrt{2^3*3^2} }{2} \qquad\qquad x_2= \dfrac{-4- \sqrt{2^3*3^2} }{2}$
<span>
</span> $x_1= \dfrac{-4+2*3 \sqrt{2} }{2} \qquad\qquad x_2= \dfrac{-4- 2*3\sqrt{2} }{2} \\ \\ \\ x_1= \dfrac{-4+6 \sqrt{2} }{2} \qquad\qquad x_2= \dfrac{-4- 6\sqrt{2} }{2} \\ \\ \\ x_1= \dfrac{-4}{2} + \dfrac{6 \sqrt{2} }{2} \qquad\qquad x_2= \dfrac{-4}{2}- \dfrac{ 6\sqrt{2} }{2} \\ \\ \\ x_1= -2 + 3 \sqrt{2} \qquad\qquad\quad x_2= -2- 3\sqrt{2} \\ \\ \\ \boxed{x= -2\pm 3\sqrt{2} } \to D)$ <span>
</span>

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3 years ago

Read 2 more answers

1(x-2)= -5.5 solve for x

STatiana [176]

Answer:

-3.5

Step-by-step explanation:

(x-2)= -5.5

x=-3.5

(add two to both sides)

6 0